DNA has thymine and RNA has uracil both of which pair with adenine.
Hope that helps.
Answer:
The options
A. A
B. B
C. C
D. E
The CORRECT ANSWER IS D.
E.
Explanation:
It is a regular occurrence for dialysis bags or dialysis tubing to be employed in permitting smooth movement of molecules when having to do with a fluid. These bags are normally evaluated to ensure that the client has adequate amount in th bag so as to be able to achieve the goal at hand.
If we have five dialysis bags being formed from a semi-permeable membrane which is impermeable to sucrose, they may be saturated with different concentrations of the sucrose with each of these bags being positioned in different beakers that have an initial amount of 0.6 M of a sucrose solution.
At ten minute intervals, the bags were massed and the weight was calculated to look for changes in the level of concentration. In this situation, the bag with the lowest initial concentration of sucrose is be the one that has its mass reducing over time and that is E.
The attached image confirms our answer as from the graph, option E shows the lowest initial concentration of sucrose.
Answer:Sclerenchyma
Explanation:Sclerenchyma is thick walled dead lignified cells, they are hard and elastic. The sclerenchyma cells are divided into two groups namely fibers and sclereids. Sclerenchymatous fibers are branched/unbranched, long, hard, pointed cells with tapering ends, thick walls, and narrow lumen.
I) Alleles is the alternative form of a gene or in other terms the variant form of a gene. If there are two alleles at a locus p and q are used to represent their frequencies. Frequencies of all alleles in a population will add up to 1.
Therefore, in this case if red allele CW is p=0.7, then the frequency of the white allele in this population (q) is 0.3.
ii) From the punnet square the expected genotypes frequencies in the offspring generation will be 0.49 CRCR (red flowers, o.42 CRCW (pink flowers) and 0.09 CWCW (white flowers).
Hey there!
Here is your answer:
Since there are not options im going to go with what i know:
<u>(Alleles)</u>
<span><u>heterozygous: A,a</u>
</span><u>homozygous: a,a</u>
<u>Therefore the Punnett square should look like this:</u>
<u>A, a</u>
<u>a IA,a I a,a</u>
<u>a IA, a I a, a</u>
Therefore the answer is 50% A,a , and 50% a, a!
If you need anymore help feel free to ask me!
Hope this helps!
~Nonportrit
