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worty [1.4K]
2 years ago
6

What is the work generated by a healthy adult who circulates 9 l of blood through the brachial artery in 10 min 2 kj?

Biology
1 answer:
Pani-rosa [81]2 years ago
5 0
You have also the total power generated is 200W

To figure out the kind of exercises, you need to master the definition of each unit. for example
power: watt (W) is joule/sec
Work: is Newton. meter = Joule

To obtain the work done by the adult, we have to convert the power (watt) into a work by multiplying by the time  (\frac{Joule}{seconds}  * seconds = Joule)
10 minutes is 60 * 10 = 600 seconds

200Watt * 600 second = 120000 joules = 120 Kj

So the work is 120Kj
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Gene A has two alleles (A1 and A2). A1A1 homozygotes are twice as likely to survive from birth to reproductive age as heterozygo
Usimov [2.4K]

Answer:

The correct answer is C: <em>0.60 </em><em>A1</em> and <em>0.40 A2</em> will be the allele frequencies in those progeny when they reach reproductive age

Explanation:

<em>Genotype</em>                                <u><em>A1A1 </em></u><em>  </em><u><em>A1A2</em></u><em> </em><u><em>A2A2 </em></u>

<em>Relative aptitude, w</em>                  1           0.5    0.5

<em>Number of individuals</em>                 40            40     40

<em>Initial allelic frequency</em>      p0= (40+20)/120=0.5    q0= (40+20)/120=0.5

<em>Zygote frequency</em>                  p2= 0.25 2pq=0.25 q2=0.625

<em>Relative contribution</em>         0.25x1=0.25     0.5x0.5=0.25 0.25x0.5=0.125

<em>of each genotype</em>              

<em>Average aptitude W</em>              W= 0.025 + 0.25 + 0.125 = 0.625

<em>Population</em>                    AA= 0.25/0.625    AB=0.25/0.625  BB=0.125/0.625

<em>Genotype frequency</em>             AA= 0.4             AB=0.4          BB=0.2  

<em>New Allelic frequency</em>       p1=0.4+(0.4/2)=0.6   q1=0.2+(0.4/2)=0.4

  • <em>Total number of individuals</em>: 120
  • <em>Initial allelic frequency</em>:

                  (number of homozygote individuals + half number of  

                   heterozygote individuals) / Total number of individuals

  • <em>Relative contribution of each genotype</em>:

                           Zygote frequency x Relative aptitude

  • <em>Average aptitude W</em>: It is the sum of relative contribution of each genotype to the next generation.  

                    wA1A1 x p2 + WA1A2 x 2 x p x q + WA2A2 x q2

  • <em>Population Genotype frequency</em>:

                Relative contribution of each genotype / Average aptitude

  • <em>Allelic frequency</em>:

                      Homozygote population genotype frequency +  half  

                           heterozygote population genotype frequency

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Answer:

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To produce motion, A cross-bridge forms between actin and the myosin heads triggering shortening of the sacromere. This shortening of the sacromere results in the contraction of the muscle fibers, which the net effect can be seen to be a shortening of the fibers

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The thing that would mostly make the results of the experiment invalid would be the students themselves. No one is built the same, and the exact same food can have very different effects on different people.

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