Answer: 4%
Out of 5000kcal, the owl loses 2300kcal which mean it could only process 2700kcal. Out of 2700kcal processed, 2500 kcal is used for cellular respiration so there is 200 kcal used to make body cells. The production efficiency would be: 200kcal/5000kcal= 4%
Answer:
d.The transferred traits were heritable.
Explanation:
Griffith's experiments with S. pneumoniae were significant because they showed that traits could be transferred from one organism to another and these transferred traits are known to be as heritable traits. In another experiment carried out by Hershey and Chase experiment it was confirmed by the results that DNA is actually the hereditary material not the protein.
Answer: herbivore, eukaryote, primary consumer
Explanation:
The red squirrel can be described by the following features.
1. Herbivore: A herbivore is an animal which is dependent upon the plant and their products for it's food requirement. Here, the red squirrel is the herbivore because it is dependent upon the spruce tree seeds for their food requirement.
2. Eukaryote: A eukaryotic organism is the one which has well define nucleus and encloses the genetic material in the nucleus. The red squirrel is a complex eukaryotic organism.
3. Primary consumer: In a food chain a primary consumer is an organism which is dependent upon plants and their food products for energy and food needs. The red squirrel is the primary consumer this is because of the fact that it consumes on the seeds of the spruce trees.
The pyloric sphincter controls the passage of food(chyme) from the stomach into the small intestine. The movement of food (chyme) through the small intestine and large intestine is controlled by paralysis. The iliocecal valve is a sphincter muscle that is normally contracted to prevent the contents of the colon from moving back into the ileum (last portion of the small intestine). The anal sphincter controls the movement food (feces) from the rectum to outside the body.
Answer:
The correct answer will be- the color change will be observed and the solution will turn purplish-black.
Explanation:
Iodine test is performed to test the presence of the carbohydrates mainly starch.
The iodine solution is chemically called potassium iodide which forms a yellow solution. The potassium iodide solution forms a complex with a starch solution which appears a purplish-black color which shows the presence of the carbohydrates.
In the given question, if we add the iodine solution to the beaker after a certain point of time then it will still form a complex with the starch and thus beaker solution will appear darker in color.
