Answer:
wifi is the best network for all, As it gets in all corners of the house.
Melinda and Bill should brainstorm to think of ways on how to have another additional income. In the case of Melinda, she could start a small business or any ways in which she could earn at home. Also, they could track down their expenses and find ways to cut down expenses to have some spare money to start paying for a life insurance policy.
The correct answer is; She can purchase OEM codes from e-commerce sites such as Amazon or eBay.
Further Explanation:
There are some sites where OEM codes cost around 110$ or higher. it will depend on which edition of Windows she plans on purchasing. The official Microsoft website sells the codes for much higher than other e-commerce sites.
There is some ways to get the older Windows for free online using a software key from a previous purchase from a friend or one you have purchased in the past. There is also a free trial that can be used for 7 days and possibly 30 days.
Learn more about Windows at brainly.com/question/1705478
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Answer:
The answer is "False"
Explanation:
The data link layer is the protocol layer within a program, which controls data movement into a physical wireless connection. This layer is a second layer, that is also known as a collection of communications applications.
- The server network, in which many clients request, and receive service from a centralized server.
- This system provides an interface, that enables a user to request server services and view the server returns results, that's why it is wrong.
Answer:
For 32 bits Instruction Format:
OPCODE DR SR1 SR2 Unused bits
a) Minimum number of bits required to represent the OPCODE = 3 bits
There are 8 opcodes. Patterns required for these opcodes must be unique. For this purpose, take log base 2 of 8 and then ceil the result.
Ceil (log2 (8)) = 3
b) Minimum number of bits For Destination Register(DR) = 4 bits
There are 10 registers. For unique register values take log base 2 of 10 and then ceil the value. 4 bits are required for each register. Hence, DR, SR1 and SR2 all require 12 bits in all.
Ceil (log2 (10)) = 4
c) Maximum number of UNUSED bits in Instruction encoding = 17 bits
Total number of bits used = bits used for registers + bits used for OPCODE
= 12 + 3 = 15
Total number of bits for instruction format = 32
Maximum No. of Unused bits = 32 – 15 = 17 bits
OPCODE DR SR1 SR2 Unused bits
3 bits 4 bits 4 bits 4 bits 17 bits
