Formula for this is as follows:
probability of her passing both 0.6/0.8 - first test and this is a fraction. 0.6/0.8
0.6/0.8= divide 0.6 by 0.8=0.75
that means probability of her passing the second test is 75%
Answer:
yes agas can hold 10 l of gas
Step-by-step explanation:
.comvmessage on it
So the given series is "16, 06, 68, 88, __"
Count all the cyclical opening in each of these numbers. For example in 16, there is a one cyclical loop present in it(the one in 6), similarly in 06 it is two(one in zero and one in 6), going ahead, in 68 it is 3(one in 6 and two in 8).
From here on things become simple: hence, the cyclical figures in these equations written down becomes 1,2,3,4,_,3.
Let's now try solving the above sequence, going by the logical reasoning the only number that can fill in the gap should be 4.
Given:
The system of inequalities is
To find:
The values of a for which the system has no solution.
Solution:
We have,
...(1)
It means the value of x is less than or equal to 5.
...(2)
It means the value of x is greater than or equal to a
Using (1) and (2), we get
But if a is great than 5, then there is no value of which satisfies this inequality.
Therefore, the system has no solution for a>5.
58% is about equal to 60%, 10% of 121 is 12.1.
12.1 * 6 = 72.6
To take this further, 58% is 2% less than 60%, or 2 times 1%. 1% of 121 is 1.21.
72.6 - (1.21 * 2) = 72.6 - 2.42 = 70.18
