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2 years ago

A science fair poster is a rectangle 48 inches long and 36 inches wide. What is the area of the poster in square feet?

2 answers:

muminat2 years ago

8 0

To find area, do length times width. 48 inches into feet is 4 feet and 36 inches into feet is 3 feet as 1 foot is 12 inches. Then to find area do 4 times 3 and you get 12 feet squared.

Lisa [10]2 years ago

7 0

Answer: 1728 square feet.

Step-by-step explanation:

We know that the area of a rectangle is given by :-

$\text{Area=length*width}$

Given: The length of the poster = 48 inches

The width of the poster = 36 inches

Now, the area of the poster is given by :-

$\text{Area=}48\times36\\\\\Rightarrow\ \text{Area=}1728\text{ inches}^2$

Hence, the area of the poster is 1728 square feet.

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2 years ago

Convert to vertex form:<br><br> y=2x^2-8x+1

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2 years ago

Marissa has twice as much money as Frank. Christina has $20 more than Marissa. If Christina has $100, how much money does Frank

qwelly [4]

Answer:

a. Take a grid that shows represents the amount of money Frank has,

Say F,

( shown below ),

b. Since, Marissa has twice as much money as Frank,

So, the amount Marissa has = 2F

If M represents the amount Marissa has,

M = 2F

c. Now, Christina has $20 more than Marissa,

Add 20 to the grid M

d. The below diagram provides enough information to determine the value of the variable m

e. The amount Christina has = M + 20 = 2F + 20

According to the question,

2F + 20 = 100

2F = 80

F = 40

Hence, the amount frank has = $ 40,

Amount Marissa has = 2(40) = $ 80,

3 0

2 years ago

James folds a piece of paper in half several times,each time unfolding the paper to count how many equal parts he sees. After fo

Snezhnost [94]

Answer:

There will be total 2048 parts of the given paper if James if able to fold the paper eleven times.

The needed function is $y = 2 ^n$

Step-by-step explanation:

Let us assume the piece of paper James decides to fold is a SQUARE.

Now, let us assume:

n : the number of times the paper is folded.

y : The number of parts obtained after folds.

Now, if the paper if folded ONCE ⇒ n = 1

Also, when the pap er is folded once, the parts obtained are TWO equal parts.

⇒ for n = 1 , y = 2 ..... (1)

Similarly, if the paper if folded TWICE ⇒ n = 2

Also, when the paper is folded twice, the parts obtained are FOUR equal parts.

⇒ for n = 2 , y = 4 ..... (2)

⇒ $y = 2^2 = 2^n$

Continuing the same way, if the paper is folded SEVEN times ⇒ n = 7

So, $y = 2^ n = 2^7 = 128$

⇒ There are total 128 equal parts.

Lastly, if the paper is folded ELEVEN times ⇒ n = 11

So, $y = 2^ n = 2^{11} = 2048$

⇒ There are total 2048 equal parts.

Hence, there will be total 2048 parts of the given paper if James if able to fold the paper eleven times.

And the needed function is $y = 2 ^n$

8 0

3 years ago

Three teachers equally shared StartFraction 4 Over 5 EndFraction of a flat of paper that was donated to the school. What fractio

melisa1 [442]

Answer:

$Each = \frac{4}{15}$

Step-by-step explanation:

Given

$Fraction = \frac{4}{5}$

$Teachers = 3$

Required

Determine fraction of each teacher

Each fraction is calculated by dividing total fraction by number of teachers as follows:

$Each = \frac{Fraction}{Teachers}$

$Each = \frac{4}{5}/3$

$Each = \frac{4}{5} * \frac{1}{3}$

$Each = \frac{4}{15}$

4 0

2 years ago