Answer:
Step-by-step explanation:
To find the zeros of the quadratic function f(x)=6x^2 + 12x – 7 we need to factorize the polynomial.
To do so, we need to use the quadratic formula, which states that the solution to any equation of the form ax^2 + bx + c = 0 is:
So, the first thing we're going to do is divide the whole function by 6:
6x^2 + 12x – 7 = 0 -> x^2 + 2x - 7/6
This step is optional, but it makes things quite easier.
Then we using the quadratic formula, where:
a=1, b= 2, c = -7/6.
Then:
So the zeros are:
Answer:
1.26 kg.
Step-by-step explanation:
We have been given that Mr. Snow bought 90 grams of Christmas candy for each of his 14 grandchildren. We are asked to find the amount of candy bought by Mr. Snow in kilograms.
First of all, we will find the amount of candy in grams by multiplying 90 grams by 14 as:
We know that 1 kilogram is equal to 1000 grams. To convert 1260 grams into kg, we will divide 1260 by 1000 as:
Therefore, Mr. Snow bought 1.26 kilograms of candy.
For a 30-60-90 triangle the sides always have the same relationship
Short leg = a
Long leg = a√3
Hypotenuse = 2a
BC is the short leg of ∆ABC
Given BC = 2
BC = a
Therefor
a = 2
AB = 2a = 4
AC = a√3 = 2√3
For ∆ACD
As above AC = 2√3
Since AC is the hypotenuse of ∆ACD
2a = 2√3
a = √3
CD = a = √3
AD = a√3 = 3
For ∆BCD
As above
BC = 2
CD = √3
Since BC is the hypotenuse of ∆BCD
2a = 2
a = 1
DB = a = 1
Answer:
I think it is maybe 19% but Idk.
Because 14 would seem to low without work and the other are pretty high so im just guessing.
Answer:
The angle between [A_F] and the base of the cone = 68.2°
The area of the base of the cone ≈ 12.57 m²
Step-by-step explanation:
The given parameters are;
The height of the cone = 5 m
The base radius of the cone = 2 m
The angle which the A
C = 120°
Therefore, we have;
The angle between [A_F] and the base of the cone = The angle between [CF] and the base of the cone
The angle between [CF] and the base of the cone = tan⁻¹(5/2) = tan⁻¹(2.5) ≈ 68.2°
∴ The angle between [A_F] and the base of the cone = The angle between [CF] and the base of the cone = 68.2°
The angle between [A_F] and the base of the cone = 68.2°
The area of the base of the cone = π × r² = π × 2² = 4·π ≈ 12.57
The area of the base of the cone ≈ 12.57 m².
