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lapo4ka [179]
2 years ago
5

What is the value of x in the equation 3x- 4y =65, when y= 4?

Mathematics
2 answers:
Alecsey [184]2 years ago
4 0

Answer:  The required value of x when y = 4 is 27.

Step-by-step explanation:  We are given to find the value of x in the following equation when y = 4 :

3x-4y=65~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

To find the value of x, first we should write equation (i) as y as the dependent variable.

From equation (i), we have

3x-4y=65\\\\\Rightarrow 3x=65+4y\\\\\Rightarrow x=\dfrac{65+4y}{3}~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(ii)

Now, substituting y = 4 in equation (ii), we get

x\\\\\\=\dfrac{65+4y}{3}\\\\\\=\dfrac{65+4\times4}{3}\\\\\\=\dfrac{65+16}{3}\\\\\\=\dfrac{81}{3}\\\\=27.

Thus, the required value of x when y = 4 is 27.

Alexus [3.1K]2 years ago
3 0
3x-4y=65

3x=65+4y

x=(65+4y)/3, when y=4

x=(65+4*4)/3

x=(65+16)/3

x=81/3

x=27
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2 years ago
According to the journal Chemical Engineering, an important property of a fiber is its water absorbency. A random sample of 20 p
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Step-by-step explanation:

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4 0
2 years ago
Catherine has $54. She plans to spend more than $20 of the money for a painting canvas. The rest will go toward paints. Each tub
kakasveta [241]

Answer:

4. 54- 8.5x>20

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Catherine only has $54, so she cannot spend more than that.

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8 0
2 years ago
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Match the following items.
Margarita [4]

Answer:

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Step-by-step explanation:

Given:

\angle DBC=40°

From the triangle, using the theorem that center angle by an arc is twice the angle it subtend at the circumference.

m\textrm{ arc CD}=2\times \angle DBC\\m\textrm{ arc CD}=2\times 40=80

Also, the diameter of the circle is BD. As per the theorem that says that angle subtended by the diameter at the circumference is always 90°,

m\angle BCD=90

From the Δ BCD, which is a right angled triangle,

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Now, using the theorem that angle between the tangent and a chord is equal to the angle subtended by the same chord at the circumference.

Here, chords CD and BC subtend angles 40 and 50 at the circumference as shown in the diagram by angles m\angle DBC\textrm{ and }m\angle BDC and EF is a tangent to the circle at point C.

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m\angle DCF=50\\\therefore m\textrm{ arc BC}=2\times m\angle DCF=2\times 50=100

Hence, all the angles are as follows:

1. m\angle ECB=50\\2. m\textrm{ arc BC}=100\\3. m\textrm{ arc CD}=80\\4. m\angle DCF=40

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