68×4≈272. easy use ur calculator ii will help u more. have fun ejoy ur day
Answer:
hannah gets £56
Step-by-step explanation:
z : h
3 : 7
24 : ?
24/3 = 8
8 x 7 = 56
£56
hope this helps
brainliest plz?
x
Answer:
Step-by-step explanation:
a )
sample mean = sum total of given data / no of data
= 415.35 / 20 = 20.76
To calculate the median we arrange the data in ascending order and take the average of 10 th and 11 th term .
= 20.50 + 20.72 / 2
= 20.61
b ) To calculate the 10% trimmed mean , we neglect the largest 10% and smallest 10 % data and then calculate the mean . Here we neglect the first two smallest and last two greatest
(18.92 + 19.25 ..... + 22.43 + 22.85) / 16
= 20.74
c )
We can easily plot the data on number line from 17 to 24
d )
Maximum value of data set = 23.71 and minimum value is 18.04
mean is 20.76 , median is 20.61 and trimmed mean is 20.74
They are between maximum and minimum values of given data . Hence there is no outliers .
Answer:
4. 54- 8.5x>20
Step-by-step explanation:
Catherine only has $54, so she cannot spend more than that.
The canvas will cost at least $20, but we don't know how much exactly.
The tubes cost $8.50 each.
So, she starts with a total budget of $54, out of which she will buy paints (8.5x) and she wants to have at least $20 left for canvas.
So, we transpose those facts into the inequity:
54 - 8.5x > 20
Answer:

Step-by-step explanation:
Given:
°
From the triangle, using the theorem that center angle by an arc is twice the angle it subtend at the circumference.

Also, the diameter of the circle is BD. As per the theorem that says that angle subtended by the diameter at the circumference is always 90°,

From the Δ BCD, which is a right angled triangle,

Now, using the theorem that angle between the tangent and a chord is equal to the angle subtended by the same chord at the circumference.
Here, chords CD and BC subtend angles 40 and 50 at the circumference as shown in the diagram by angles
and EF is a tangent to the circle at point C.
Therefore, 
Again, using the same theorem as above,

Hence, all the angles are as follows:
