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Andrew [12]
2 years ago
15

Lucas has five buttons in a container. Each button is a different shape. There is a star, an oval, a hexagon, a circle, and a he

art. He picks one button, replaces it, and then picks another button. The sample size for this compound event is  ___  Suppose one square-shaped button is added to the container. If Lucas repeats the same picking process, then the sample size would be ____
Mathematics
2 answers:
Readme [11.4K]2 years ago
7 0
Part A: There are five buttons in all in all in the given item. The item above can be answered through the fundamental principles of counting. 

There are 5 items to choose from during the first pick. Because the shape can be returned and picked again, there are also 5 items to choose from in the second pick. Multiplying them,
                               n = 5 x 5 = 25
Therefore, the sample size for the compound event is equal to 25.

Part B: The same concept can be used in this part of the item; however, instead of 5 there are 6 buttons to choose from.
                              n = 6 x 6 = 36

Hence, the sample size of this picking process is 36. 
MAVERICK [17]2 years ago
6 0

Answer: is  25,36

Step-by-step explanation:

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What is the MAD of the data set? <br><br> {13, 6, 3, 7, 11}<br><br> Enter your answer in the box.
frosja888 [35]
13 + 6 + 3 + 7 + 11 = 40
;
40 ÷ 5 = 8
;
13 - 8 = 5
6 - 8 = |-2| = 2
3 - 8 = |-5| = 5
7 - 8 = |-1| = 1
11 - 8 = 3
;
5, 2, 5, 1, 3
5 + 2 + 5 + 1 + 3 = 16
16 ÷ 5 = 3.2 
;
Mean Absolute Deviation is 3.2.

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3 0
2 years ago
The lees rented a car for 4 weeks.The santos rented a car for 2 weeks.Whose weekly rentsl cost was lower?
Romashka-Z-Leto [24]
The santos because they rented the car for two weeks, while the others rented for four.
5 0
2 years ago
Read 2 more answers
A student placement center has requests from five students for interviews regarding employment with a particular consulting firm
bagirrra123 [75]

Answer: a) 1 / 10

b) 3 / 10

c) 1 / 5

d) 3 / 5

Step-by-step explanation:

Total number of requests five students for interviews regarding employment with the consulting firm = 5

Number of students that are maths majors = 3

Probability of selecting a maths student is 3 / 5

Number of students that are statistics majors = 2

Probability of selecting a statistics student is 2 / 5

a) the probability that both selected students are statistics majors

= 2 / 5 × 1 / 4 = 2 / 20 = 1 / 10

b) the probability that both students are math majors

= 3 / 5 × 2 / 4 = 6 / 20 = 3 / 10

c) the probability that at least one of the students selected is a statistics major will be p( one statistics and the other, maths) + p( one maths and the other, statistic) - p( both are mathematics)

= (2 / 5 × 1 / 4 ) + ( 2 / 5 × 3 / 4 ) - (3 / 5 × 2 / 4)

= 2 / 10 + 6 / 20 - 6 / 20

= 1 / 5 + 3 / 10 - 3 / 10

= 1 / 5

d) the probability that the selected students have different majors is p(one is maths and the other is statistics) + p(one is statistics and the other is maths)

(3 / 5 × 2 / 4) + (2 /5 × 3 / 4)

= 6 / 20 + 6 / 20 = 12 / 20

= 3 / 5

3 0
2 years ago
On the last day of vacation, the Ramirez family drove 252 miles from a state park to its home. The drive covered 35% of the tota
kirill115 [55]

Answer:

Step-by-step explanation:

35 percent of total miles traveled (say T)is 252 miles.

(35/100) * T=252

T=(252*100)/35 => T=720 miles

So total distance the Ramirez family traveled during its vacation is 720 miles

4 0
2 years ago
Read 2 more answers
In 2019, approximately 97.4% of all the runners who started the Boston Marathon (in Boston, Massachusetts, USA) were able to com
PtichkaEL [24]

Answer:

The probability that exactly 97 of them finished the marathon​ is 0.221.

Step-by-step explanation:

We are given that in 2019, approximately 97.4% of all the runners who started the Boston Marathon were able to complete the 42.2 km race.

100 runners are chosen at random.

The above situation can be represented through the binomial distribution;

P(X = x) = \binom{n}{r} \times p^{r} \times (1-p)^{n-r};x = 0,1,2,3,......

where, n = number of trials(or samples) taken = 100 runners

           r = number of success = exactly 97

           p = probability of success which in our question is the probability

                 that runners finished the marathon​, i.e; p = 0.974

So, X ~ Binom(n = 100, p = 0.974)

Now, the probability that exactly 97 of them finished the marathon​ is given by = P(X = 97)

         P(X = 97) = \binom{100}{97} \times 0.974^{97} \times (1-0.974)^{100-97}

                          = 161700 \times 0.974^{97} \times 0.026^{3}

                          = 0.221

Hence, the required probability is 0.221.

6 0
2 years ago
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