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Julli [10]
2 years ago
7

Maria studied the traffic trends in India. She found that the number of cars on the roads increases by 10% each year. If there w

ere 80 million cars in year 1 of her study, how many more cars were on the road in year 3 compared to year 2?
Mathematics
2 answers:
Nitella [24]2 years ago
8 0
Year 2 is 88 million and in year 3 it is 96.8 million. 96.8 million-88 million it makes 8.8 million. So the answer is 8.8 million people.

zmey [24]2 years ago
3 0

Answer: 8.8 million


Step-by-step explanation:

Given: The number of cars in year 1= 80 million

As she  found that the number of cars on the roads increases by 10% each year.

Now, 10% of 80 million=0.10\times80\ million=8\ million

Thus, the number of cars in year 2= 80 million+8 million=88 million

Now, 10% of 88 million=0.10\times88\ million=8.8\ million

Thus, the number of cars in year 3= 88 million+8.8 million=96.8 million

Now, the difference in the cars in  year 3 compared to year 2=96.8 million-88 million

Thus, the difference in the cars in  year 3 compared to year 2=8.8 million

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Compare and contrast XY with XY.
mojhsa [17]

Answer:

{}                                                                                                    XY                \overline {XY}

Represent a distance {}                                                                 √

Represent a segment {}                                                                                     √

Represent a numerical value {}                                                     √

Represent a geometric figure                                                                           √

Can be found by applying the ruler postulate  {}                         √

Can be be duplicated with a compass and a straight edge                          √

Step-by-step explanation:

The difference between XY and \overline {XY} are that the points XY represents the distance between two points having a numerical value whose value can be found by using a ruler to find difference in the numbers on the ruler that coincides with the points, while

4 0
2 years ago
Elisse has 20 meters of ribbon how many 15 cm of ribbon can be cut from it
ASHA 777 [7]

Answer:

133 pieces of 15cm can be cut from the ribbon.

Step-by-Step Explanation:

Length of ribbon = 20 meters

Length needed to be cut = 15 cm

We will convert meters into centimeters.

1 meter = 100 cm

20 meters = 2000 cm

Number of pieces = \frac{2000}{15}

Number of pieces = 133.33

Rounding off to nearest whole number = 133

Hence,

133 pieces of 15cm can be cut from the ribbon.

8 0
2 years ago
You have a coupon for a local craft store that is for 40% off one item. You would like to purchase a glue gun for $8.99 and a ba
Yanka [14]

Answer:

$26.06

Step-by-step explanation:

You would like to purchase a glue gun for $8.99 and a basket for $25.99. The highest-priced item is a basket for $25.99. So, the coupon will take the discount off for this item.

The new price of the basket is

\$25.99\cdot (1-0.4)=\$25.99\cdot 0.6=\$15.594

The total cost of your buying  is

\$8.99+\$15.594=\$25.584

There will be a 6% sales tax added to the price of all items. So, the end cost is

\$25.584\cdot (1+0.06)=\$25.584\cdot 1.06=\$26.05904\approx \$26.06

4 0
2 years ago
Complete the steps for solving 7 = –2x2 + 10x. Factor out of the variable terms. inside the parentheses and on the left side of
Mamont248 [21]

we have

7=-2x^{2} +10x

Factor the leading coefficient

7=-2(x^{2} -5x)

Complete the square. Remember to balance the equation by adding the same constants to each side

7-12.50=-2(x^{2} -5x+2.5^{2})

-5.50=-2(x^{2} -5x+2.5^{2})

Divide both sides by -2

2.75=(x^{2} -5x+2.5^{2})

Rewrite as perfect squares

2.75=(x-2.5)^{2}

Taking the square roots of both sides (square root property of equality)

x-2.5=(+/-)\sqrt{2.75}

Remember that

\sqrt{2.75}=\sqrt{\frac{11}{4}}= \frac{\sqrt{11}}{2}

x-2.5=(+/-)\frac{\sqrt{11}}{2}

x=2.5(+/-)\frac{\sqrt{11}}{2}

x=2.5+\frac{\sqrt{11}}{2}=\frac{5+\sqrt{11}}{2}

x=2.5-\frac{\sqrt{11}}{2}=\frac{5-\sqrt{11}}{2}

<u>the answer is</u>

The solutions are

x=\frac{5+\sqrt{11}}{2}

x=\frac{5-\sqrt{11}}{2}


5 0
2 years ago
Read 2 more answers
I NEED HELP PLEASE, THANKS! :) Use the graph to determine the domain and range of the relation, and state whether the relation i
Mandarinka [93]

Answer:

Domain: All numbers greater than or equal to 0. By definition, the domain of a graph, is the possible x values.

Range: All real numbers. By definition, the range is all possible x values.

Not a function. A function has y value for every x value.

3 0
2 years ago
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