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Julli [10]
2 years ago
7

Maria studied the traffic trends in India. She found that the number of cars on the roads increases by 10% each year. If there w

ere 80 million cars in year 1 of her study, how many more cars were on the road in year 3 compared to year 2?
Mathematics
2 answers:
Nitella [24]2 years ago
8 0
Year 2 is 88 million and in year 3 it is 96.8 million. 96.8 million-88 million it makes 8.8 million. So the answer is 8.8 million people.

zmey [24]2 years ago
3 0

Answer: 8.8 million


Step-by-step explanation:

Given: The number of cars in year 1= 80 million

As she  found that the number of cars on the roads increases by 10% each year.

Now, 10% of 80 million=0.10\times80\ million=8\ million

Thus, the number of cars in year 2= 80 million+8 million=88 million

Now, 10% of 88 million=0.10\times88\ million=8.8\ million

Thus, the number of cars in year 3= 88 million+8.8 million=96.8 million

Now, the difference in the cars in  year 3 compared to year 2=96.8 million-88 million

Thus, the difference in the cars in  year 3 compared to year 2=8.8 million

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Answer:

Intercepts at (-1, 0) and (0, 1).

Step-by-step explanation:

The double intercept form for the equation of a line is

ax + by = 1

-1 = -y + x

<em> y = 0 </em>

<em> </em>x = -1     Multiply each side by -1

-x = 1

The <em>x-intercept</em> is at (-1, 0).

=====

<em> x = 0 </em>

-1 = -y     Multiply each side by -1

y = 1

The <em>y-intercept</em> is at (0, 1).

=====

The graph (see below) is a straight line passing through the points (-1, 0) and (0, 1).


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2 years ago
$1.12 for 8.2 ounces? Unit Rate
Reil [10]
That is around 13 or 14 cents. The specific answer is 13.65853659 cents, but you can either round up to 14 or round down to 13 (rounding up to 14 is the correct way to do it.)

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4 0
2 years ago
Talulah is an ecologist who studies the change in the penguin population of Antarctica over time. She observed that the populati
Oksana_A [137]

Answer:

P(t) = 27000 * (1/9)^(t/4)

Step-by-step explanation:

This problem can me modelled with an exponencial formula:

P = Po * (1+r)^t

Where P is the final value, Po is the inicial value, r is the rate and t is the amount of time.

In this problem, we have that the inicial population/value is 27000, the rate is -8/9 (negative because the population decays), and the time t is in months, so as the rate is for every 4 months, we use the value (t/4) in the exponencial.

So, our function will be:

P(t) = 27000 * (1-8/9)^(t/4)

P(t) = 27000 * (1/9)^(t/4)

8 0
2 years ago
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A sample statistic , such as x bar, that estimates the value of the corresponding population parameter is known as
Orlov [11]
A sample statistic , such as x bar, that estimates the value of the corresponding population parameter is known as a control chart.
6 0
2 years ago
NEED HELP ON NUMBER 13 AND 14
Kazeer [188]

Answer:

Question 13: For age groups y=1 and y=1.3 response is 8 microseconds.

Question 14: The club was making a loss between 11.28 and 4.88 years.

Step-by-step explanation:

Question 13:

The age group y for which the response rate R is 8 microseconds  is given by the solution of the equation

8=y^4 +2y^3 - 4y^2 -5y +14.

We graph this equation and find the solutions to be

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Thus only for age groups y=1 and y=1.3 the response is 8 microseconds.

Question 14:

The footbal club is making a loss when p(t)

Or

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We graph this inequality and find the solutions to be

t and 4.88

Since in the real world only positive values for t are valid, we take the the second solution to be true.

Thus the club was making a loss in years 4.88

5 0
2 years ago
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