Answer: you can use 260 min, 60 min at a fixed price ($20) and extra 200.
Step-by-step explanation:
C(x) = 20 + 0.20(x − 60)
C(x) ≤ 60
20 + 0.20(x − 60) ≤ 60
0.20(x − 60) ≤ 60 - 20
0.20x - 12 ≤ 40
0.20x ≤ 40 + 12
0.20x ≤ 52
x ≤ 52/0.2
x ≤ 260
This way, you can use 260 min, 60 min at a fixed price ($20) and extra 200.
Car value at the time of purchase $15, 250 (2012)
Rate of depreciation 7.5%
1) y = 15250 ( 1- 0.075)^x
y = 15250 (0.925)^x (x tis the number of years that passed since purchase)
2) y = 15250 * ( 0.925)^8 = 8173.42
Answer:
your... syllabus is different from mine....
Step-by-step explanation:
which class u study
