How can you prove that a constructed line is parallel to a given line? assume that the transversal line is not perpendicular to
1 answer:
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Answer:
The graph in the attached figure
Step-by-step explanation:
we have
Remember that the radicand must be greater than or equal to zero
so
solve for x
subtract 2 both sides
The domain is the interval [-2,∞)
All real number greater than or equal to -2
For x=-2
so
The range is the interval [0,∞)
All real number greater than or equal to 0
Find the y-intercept
Remember that the y-intercept is the value of y when the value of x is equal to zero
For x=0
The y-intercept is the point (0,4.243)
therefore
The graph in the attached figure
The complete question in the attached figure
we know that
the equation of a parabola is
y=a(x-h)²+k
where
(h,k) is the vertex --------> (h,k)--------> (-1,2)
so
y=a(x+1)²+2
point (2,20)
for x=2
y=20
20=a(2+1)²+2--------> 20=a*9+2--------> 9*a=18---------> a=2
the equation of a parabola is
y=a(x+1)²+2-------> y=2(x+1)²+2
therefore
the answer is the option
<span>C) f(x) = 2(x + 1)2 + 2</span>
we know that
the equation of a parabola is
y=a(x-h)²+k
where
(h,k) is the vertex --------> (h,k)--------> (-1,2)
so
y=a(x+1)²+2
point (2,20)
for x=2
y=20
20=a(2+1)²+2--------> 20=a*9+2--------> 9*a=18---------> a=2
the equation of a parabola is
y=a(x+1)²+2-------> y=2(x+1)²+2
therefore
the answer is the option
<span>C) f(x) = 2(x + 1)2 + 2</span>