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Llana [10]
2 years ago
6

If an eagle and a bumblebee are traveling at 8 km/hr, which has more momentum explain

Mathematics
1 answer:
Aleksandr-060686 [28]2 years ago
6 0
The eagle would have more momentum because it has a larger mass.
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What is 7.630 in word form
Furkat [3]
Seven point six three
6 0
2 years ago
Read 2 more answers
HELP!!!!!!<br><br> y = 6kx - 2; m = 2/3
Mrrafil [7]

Answer:

k=1/9

Step-by-step explanation:

6k is the slope , and you actual slope(m) is given, hence,make em equal to each other:

6k = 2/3

k = 2/3(6) [Divide both sides by 6]

k = 1 /9 [Simplify]

Hope this helps!

Mark brainliest if you think I helped!

Would really appreciate!

7 0
2 years ago
The price per night for a hotel room is different at three different hotels.
Damm [24]
I think you meant it to be not repeating 3 times so
You do 192/3 is 60*3= 180 leaving you with 12 which is 4*3. So 64 is A
Then it’s 300/5 which is 60
455/7. So first see, if I multiply 7 by 60 is it over or under. If it’s over then B is the least and if it is less then C is the least. So 7 *60 is 420
C Being greater, b costs least per night
4 0
2 years ago
Upgrading a certain software package requires installation of 68 new files. Files are installed consecutively. The installation
ser-zykov [4K]

Answer:

The probability that the whole package is uppgraded in less then 12 minutes is 0,1271

Step-by-step explanation:

The mean distribution for the length of the installation (in seconds) of the programs will be denoted by X. Using the Central Limit Theorem, we can assume that X is normal (it will be pretty close). The mean of X is 15 and the variance is 15, hence, the standard deviation is √15 = 3.873.

We want to find the probability that the full installation process takes less than 12 minutes = 720 seconds. Then, in average, each program should take less than 720/68 = 10.5882 seconds to install. Hence, we want to find the probability of X being less than 10.5882. For that, we will take W, the standariation of X, given by the following formula

W = \frac{X-\mu}{\sigma} = \frac{X-15}{3.873}

We will work with \phi , the cummulative distribution function of the standard Normal variable W. The values of \phi can be found in the attached file.

P(X < 10.5882) = P(\frac{X-15}{3.873} < \frac{10.5882-15}{3.873}) = P(W < -1,14)

Since the density function of a standard normal random variable is symmetrical, then \phi(-1.14) = 1-\phi(1.14) = 1-0.8729 = 0.1271

Therefore, the probability that the whole package is uppgraded in less then 12 minutes is 0,1271.

Download pdf
7 0
2 years ago
Pat's ending balance on his debit card last month was $233.55. This month he had $542 worth of purchases and $710 worth of depos
ad-work [718]

Answer:

$401.55                              

Step-by-step explanation:

Given:

Pat's ending balance on his debit card last month was $233.55,<u> we can consider it as opening balance for this month as carry forwarded.</u>

This month he had $542 worth of purchases.

This month he had $710 worth of deposits.

Question asked:

What is his ending balance for this month ?

Solution:

We can easily find the ending balance by subtracting purchase amount as it will reduce the balance and we will add deposits as it increase the balance of debit card.

Opening balance of debit card =  $233.55

Purchases worth of = $542

Deposit worth of = $710

<em><u>Ending balance for this month = Opening balance of debit card + Deposit - Purchases </u></em>

Ending balance for this month =  $233.55 +  $710 - $542  

                                                  = $943.55 - $542 = $401.55        

Therefore, the ending balance for this month in his debit card is $401.55                              

4 0
2 years ago
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