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horrorfan [7]
2 years ago
6

Your three blood cell types have different sizes, shapes, and functions. Yet they all started out alike. Within each cell of you

r body there are ___________, which give the instructions for cell processes. These instructions include the differentiation of your blood cells
Biology
2 answers:
sweet [91]2 years ago
6 0

Answer:

Your three blood cell types have different sizes, shapes, and functions. Yet they all started out alike. Within each cell of your body there are chromosomes which give the instructions for cell processes. These instructions include the differentiation of your blood cells

Explanation:

In the chromosomes the DNA is packed, from its sequence and from other control mechanisms the genetic expression is regulated and instructions are given to generate one or another type of cell. This happens because there is a differential expression of the different genes according to the cell type.

sergejj [24]2 years ago
5 0
It would be chromosomes these are the bodys blue prints or instructions <span />
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<span>Below are useful in creating a phylogenetic tree of a vertebrate taxon:</span>

<span>1.      </span>DNA sequence from living organism or also known as genetic sequence, it is used to determine strand of DNA

<span>2.      </span>Behavioral data from living species, a method to identify the origin of individual in behavioral aspect

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2 years ago
Do autotrophs need to perform cellular respiration?
nydimaria [60]
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Yes, autotrophs need to perform cellular respiration.

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Some single-celled protists, such as paramecia, live in an extremely hypotonic environment and have contractile vacuoles that
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7 0
2 years ago
The thin segment of the nephron loop's descending limb ________. The thin segment of the nephron loop's descending limb ________
vovangra [49]

Answer:

The correct answer is ''aids in the passive movement of water out of the tubule''

Explanation:

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5 0
2 years ago
Pseudomonas sp. has a mass doubling time of 2.4 h when grown on acetate. The saturation constant using this substrate is 1.3 g/l
erastova [34]

Answer:

a)  Cell concentration when the dilution rate is one-half of the maximum is  0.598g cell/L

b) the substrate concentration when the dilution rate is 0.8 D_{max}   is 5.2g/l

c) the maximum dilution rate is : 0.41 h⁻¹

d)  the cell productivity at 0.8  D_{max}   is 2.40g cell/L

Explanation:

Given data :

Mass doubling time of Pseudomonas sp. = 2.4 hr

Saturation constant = 1.3 g/L

Cell yield  on acetate = 0.46g cell/g acetate

We are to find;

a. Cell concentration when the dilution rate is one-half of the maximum.

Here, cell yield =amount of cell produced / amount of substrate consumed.

[S] at 0.5D max is determined using the Monod's equation.

Using the formula :

D = \frac {D_{max}[S] }{ks+[S]}

, where D is the dilution rate,

[S] is substrate concentration; &

Ks is the saturation constant.

By replacing the values, we get :

0.5 = \frac{S}{1.3+[S]}

\\\0.65=0.5[S]

[S]=1.3g/L

The cell concentration at 0.5Dmax= cell yield x substrate consumed at 0.5Dmax.

=0.46×1.3

= 0.598g cell/L

b)

Substrate concentration when the dilution rate is 0.8 D_{max}    is calculated as:

D = \frac {D_{max}[S] }{ks+[S]}

0.8=[S]/1.3+[S]

1.04+0.8[S]=[S]

[S]= 5.2g/L

Therefore ,  the substrate concentration when the dilution rate is 0.8 D_{max}   is 5.2g/l

c)

Maximum dilution rate is calculated using the expression D_{max} = \frac{1}{time}

=1/2.4

=0.41 h⁻¹

So, the maximum dilution rate is : 0.41 h⁻¹

d)

The cell productivity at 0.8 D_{max} can be calculated by multiplying the amount  of the cell yield with the amount of the substrate consumed at 0.8D_{max}  

Cell yield = \frac {cell \ productivity \ at \  0.8Dmax}{amount \ of \ substrate\ consumed \at\ 0.8 \D_{max}}

Cell productivity at 0.8 D_{max}    = 0.46 × 5.2

=2.40g cell/L

Therefore, the cell productivity at 0.8  D_{max}   is 2.40g cell/L

5 0
2 years ago
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