Mr. Johnson leaves on a trip planning to travel 24 mph. How fast must his son James travel to overtake him in 5 hours if he star
1 answer:
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Answer:
a. b. 6.1 c. 0.6842 d. 0.4166 e. 0.1194 f. 8.5349
Step-by-step explanation:
a. The distribution of X is normal with mean 6.1 kg. and standard deviation 1.9 kg. this because X is the weight of a randomly selected seedless watermelon and we know that the set of weights of seedless watermelons is normally distributed.
b. Because for the normal distribution the mean and the median are the same, we have that the median seedless watermelong weight is 6.1 kg.
c. The z-score for a seedless watermelon weighing 7.4 kg is (7.4-6.1)/1.9 = 0.6842
d. The z-score for 6.5 kg is (6.5-6.1)/1.9 = 0.2105, and the probability we are seeking is P(Z > 0.2105) = 0.4166
e. The z-score related to 6.4 kg is and the z-score related to 7 kg is
, we are seeking P(0.1579 < Z < 0.4737) = P(Z < 0.4737) - P(Z < 0.1579) = 0.6821 - 0.5627 = 0.1194
f. The 90th percentile for the standard normal distribution is 1.2815, therefore, the 90th percentile for the given distribution is 6.1 + (1.2815)(1.9) = 8.5349
Answer:
Percent form: 41.65%
Fraction form:
Step-by-step explanation:
33% of men support John Smith.
67% of women support John Smith.
Lets say, for instance, that there are 20 polled individuals -- 10 women and 10 men.
However, since 1.5 times as many men voted as women, we have to apply our poll to 15 men and 5 women.
33% of the 15 men makes 5 men who voted for Smith and 10 who did not.
67% of the 5 women makes 3.33 women who voted for Smith and 1.67 who did not.
Add these numbers together.
8.33 total voters were cast for John Smith, while 11.67 were not.
Now, divide 8.33 by 20 and multiply by 100 to obtain a percentage.
41.65% of voters voted for John Smith according to the results of the poll.