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blsea [12.9K]
2 years ago
4

Eighty-three million, twenty three thousand, seven in standard form?

Mathematics
2 answers:
kompoz [17]2 years ago
6 0
Eighty-three million, twenty-three thousand and seven in standard form is 83,023,007
Darya [45]2 years ago
5 0
<span>Eighty-three million, twenty-three thousand and seven in standard form is 83,023,007</span>
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N(17+x)=34x−r<br> I need to solve for x
Paraphin [41]

Answer:

The value of x is, x= \frac{17N+r}{34-N}

Explanation:

Given: N(17+x)=34x-r

Distributive Property states that when a number is multiplied by the sum of two numbers, the first number can be distributed to both of those numbers and multiplied by each of them separately.

If a\cdot(b+c) =a\cdot b + a\cdot c

Now, using distributive property on left hand side of the given expression as:

N\cdot 17+N\cdot x = 34x-r or 17N+Nx = 34x-r

Addition Property of equality state that we add the same number from both sides of an equation.

Add r to both sides of an equation:

17N+Nx+r=34x-r+r

Simplify:

17N+Nx+r=34x

Subtraction Property of equality state that we subtract the same number from both sides of an equation.

Subtract Nx from both sides of an equation;

17N+Nx+r-Nx=34x-Nx

Simplify:

17N+r=34x-Nx

or

17N+r=x(34-N)

Division Property of equality states that we divide the same number from both sides of an equation.

Divide by (34-N) to both sides of an equation;

\frac{17N+r}{34-N}= \frac{x(34-N)}{34-N}

On Simplify:

x= \frac{17N+r}{34-N}





4 0
2 years ago
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at a track meet, jacob and daniel compete in the 220 m hurdles. daniel finishes in 3/4 of a minute. jacob finishes with 5/12 of
Scrat [10]

I hope this help

Jacob  is the faster time

6 0
2 years ago
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Lola tossed a coin twice. She made a tree diagram to show the possible outcomes. Which tree diagram shows the sample space for t
trapecia [35]

Answer:

Sample space for two tosses of a coin [HH, TT, HT,TH]

Step-by-step explanation:

Im sorry if you got it wrong :(

please tell me in the comments

8 0
2 years ago
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Unit 3 parallel and perpendicular lines homework 4 parallel line proofs
Alex17521 [72]

Answer:

1) c ║ d by consecutive interior angles theorem

2) m∠3 + m∠6 = 180° by transitive property

3) ∠2 ≅ ∠5 by definition of congruency

4) t ║ v                                    {}                   Corresponding angle theorem

5) ∠14 and ∠11  are supplementary         {}  Definition of supplementary angles

6) ∠8 and ∠9  are supplementary    {}        Consecutive  interior angles theorem

Step-by-step explanation:

1) Statement                                {}                                     Reason

m∠4 + m∠7 = 180°                                 {}   Given

m∠4 ≅ m∠6                                {}              Vertically opposite angles

m∠4 = m∠6                               {}                Definition of congruency

m∠6 + m∠7 = 180°                                {}    Transitive property

m∠6 and m∠7 are supplementary     {}     Definition of supplementary angles

∴ c ║ d                               {}                       Consecutive interior angles theorem

2) Statement                                {}                                     Reason

m∠3 = m∠8                                 {}           Given

m∠8 + m∠6 = 180°                {}                 Sum of angles on a straight line

∴ m∠3 + m∠6 = 180°               {}               Transitive property

3) Statement                                {}                                     Reason

p ║ q                                 {}                    Given

∠1 ≅ ∠5                               {}                  Given

∠1 = ∠5                               {}                   Definition of congruency

∠2 ≅ ∠1                               {}                  Alternate interior angles theorem

∠2 = ∠1                               {}                   Definition of congruency

∠2 = ∠5                                  {}               Transitive property

∠2 ≅ ∠5                                  {}              Definition of congruency.

4) Statement                                {}                                     Reason

∠1 ≅ ∠5                                  {}                Given

∠3 ≅ ∠4                               {}                  Given

∠1 = ∠5                               {}                   Definition of congruency

∠3 = ∠4                               {}                  Definition of congruency

∠5 ≅ ∠4                               {}                 Vertically opposite angles

∠5 = ∠4                               {}                  Definition of congruency

∠5 = ∠3                                  {}               Transitive property

∠1 = ∠3                                  {}                Transitive property

∠1 ≅ ∠3                                  {}                Definition of congruency.

t ║ v                                    {}                   Corresponding angle theorem

5) Statement                                {}                                     Reason

∠5 ≅ ∠16                                  {}              Given

∠2 ≅ ∠4                               {}                  Given

∠5 = ∠16                               {}                  Definition of congruency

∠2 = ∠4                               {}                   Definition of congruency

EF ║ GH                               {}                  Corresponding angle theorem

∠14 ≅ ∠16                               {}                Corresponding angles

∠14 = ∠16                               {}                 Definition of congruency

∠5 = ∠14                                  {}               Transitive property

∠5 + ∠11 = 180°                {}                       Sum of angles on a straight line

∠14 + ∠11 = 180°                                {}      Transitive property

∠14 and ∠11  are supplementary         {}  Definition of supplementary angles  

6) Statement                                {}                                     Reason

l ║ m                                 {}                      Given

∠4 ≅ ∠7                               {}                  Given

∠4 = ∠7                               {}                   Definition of congruency

∠2 ≅ ∠7                               {}                  Alternate angles

∠2 = ∠7                               {}                   Definition of congruency

∠2 = ∠4                                  {}               Transitive property

∠2 ≅ ∠4                               {}                  Definition of congruency

∠2 and ∠4 are corresponding angles   {} Definition

DA ║ EB                               {}                  Corresponding angle theorem

∠8 and ∠9  are consecutive  interior angles    {} Definition

∠8 and ∠9  are supplementary    {}        Consecutive  interior angles theorem.

6 0
2 years ago
two friends went rowing on the river. they traveled with current for 3 hours. the way back took them 4 hours and 48 minutes. fin
N76 [4]

Answer:

1.5 mph

Step-by-step explanation:

The speed in the still water = 6.5 mph.

The speed of the current = x mph.

1. Two friends traveled with current for 3 hours. The speed with the current is 6.5 + x mph, so they traveled 3(x+6.5) miles.

2. Two friends traveled against the current for 4 hours and 48 minutes that is 4\dfrac{4}{5}=4.8 hours. The speed against the current is 6.5 - x mph, so they traveled 4.8(6.5-x) miles.

They traveled the same distance with the current and against the current, hence,

3(x+6.5)=4.8(6.5-x)

Solve this equation:

3x+19.5=31.2-4.8x\\ \\3x+4.8x=31.2-19.5\\ \\7.8x=11.7\\ \\x=1.5\ mph

4 0
2 years ago
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