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Katen [24]
2 years ago
13

What is the scale factor of triangle ABC to DEF ?

Mathematics
2 answers:
bekas [8.4K]2 years ago
8 0

Answer:  The correct option is (A). 3.

Step-by-step explanation:  We are given to find the scale factor of dilation from ΔABC to ΔDEF.

As shown in the figure, the lengths of the sides of ΔABC to ΔDEF are

AB = 5 units, BC = 4 units, CA = 3 units,

DE = 15 units, EF = 12 units, FD = 9 units.

We know that the scale factor is given by

S=\dfrac{\textup{length of a side of the dilated figure}}{\textup{length of the corresponding side of the original figure}}.

Therefore, the scale factor of dilation from from ΔABC to ΔDEF is

S=\dfrac{DE}{AB}=\dfrac{15}{5}=3.

Thus, the required scale factor is 3.

Option (A) is correct.

olasank [31]2 years ago
3 0

Answer: the answer is 3.

Step-by-step explanation:

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According to the Rational Root Theorem, which could be a factor of the polynomial f(x) = 60x4 + 86x3 – 46x2 – 43x + 8?
kaheart [24]
<span> If P(x) is a polynomial with integer coefficients and if is a zero of P(x) ( P( ) = 0 ), then p is a factor of the constant term of P(x) and q is a factor of the leading coefficient of P(x) .

</span><span>A. x – 6
</span><span>60(6)^4 + 86(6)^3 – 46(6)^2 – 43(6) + 8 = 94430
</span><span>
B. 5x – 8
</span>60(8/5)^4 + 86(8/5)^3 – 46(8/5)^2 – 43(8/5) + 8 = 566.912<span>

C. 6x – 1
</span>60(1/6)^4 + 86(1/6)^3 – 46(1/6)^2 – 43(1/6) + 8 = 0 -------> ANSWER
<span>
D. 8x + 5
</span>60(-5/8)^4 + 86(-5/8)^3 – 46(-5/8)^2 – 43(-5/8) + 8 = 5.07
3 0
2 years ago
Read 2 more answers
What is the range of the function graphed below?
Xelga [282]
<h2>Answer:</h2>

Option: B is the correct answer.

The range of the function is:

        B.      5 < y < ∞

<h2>Step-by-step explanation:</h2>

Range of a function--

The range of a function is the set of all the values that is attained by the function.

By looking at the graph of the function we see that the function tends to 5 when x→ -∞ and the function tends to infinity when x →∞

Also, the function is a strictly increasing function.

This means that the function takes every real value between 5 and ∞ .

i.e. The range of the function is: (5,∞)

          Hence, the answer is:

                Option: B

8 0
2 years ago
Here are the monthly charges for jo’s Mobile phone. Monthly charge £16,150 free minutes,then 13p per minute,150 free texts,then
zhuklara [117]

Answer:

16,652

Step-by-step explanation:

5 0
2 years ago
A row of tiny red beads is placed at the beginning and at the end of a 20‐centimeter bookmark.
AlladinOne [14]

Answer:

51 rows

Step-by-step explanation:

Given

Length of bookmark = 20cm

Distance between beads = 4mm

Required

Number of rows of beads

First, the distance between the rows of beads must be converted to cm

if 1mm = 0.1cm

then

4mm = 4*0.1cm

4mm = 0.4 cm

This means that each row of beads is placed at 0.4 cm mark.

The distance between each row follows an arithmetic progression and it can be solved as follows;

T_n = a + (n-1)d

Where Tn = 20cm (The last term)

a = 0 cm (The first term)

d = 0.4cm (The distance between each row of beads)

n = ?? (number of rows)

Solving for n; we have the following;

T_n = a + (n-1)d becomes

20 = 0 + (n-1)0.4

20 =  (n-1)0.4

DIvide both sides by 0.4

\frac{20}{0.4} =  \frac{(n-1)0.4}{0.4}

50 =  (n-1)

50 =  n-1

Add 1 to both sides

50 + 1=  n-1 + 1

n = 51

Hence, the number of rows of beads is 51

4 0
2 years ago
The size of a television screen is given as 95 cm, correct to the nearest 5 cm.
alexdok [17]

Answer:

The upper bound is 97.5 cm

Step-by-step explanation:

The upper bound is given as the value that is larger than or equal to all values in a data set, for example, in the data set, {3, 6, 16, 23, 25}, an upper bound  is 25, however, where the accuracy of the data is given, the upper bound can be found by the following relation

Where the number is given to the nearest 100, add and subtract  half of hundred to obtain the upper bound and lower bound respectively

For the question, given that the size of the television is given as 95 cm, correct to the nearest 5 cm, we add add half of 5 cm to get the upper bound as follows;

Upper bound = 95 cm + 5/2 cm = 97.5 cm

The upper bound = 97.5 cm.

5 0
2 years ago
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