Answer:
Step-by-step explanation:
<u>Right Triangles
</u>
In a right triangle, one of the internal angles is 90°. When this happens, there is always a longer side, called hypotenuse and two shorter sides, called legs. They relate to Pythagoras's theorem. The basic trigonometric relations also stand, including
where a is the opposite leg to 
and c is its adjacent led .
In our problem, we have a statue being looked by a person in such a way that the top of the statue forms an angle of 8° with the horizontal and the base of the statue forms an angle of 14° down. We also know the distance from the person to the statue is 50 ft. The situation is shown in the image below.
The height of the statue is h=a+b, where
Thus
Answer:
a) 0.0228
b) 94.6
Step-by-step explanation:
The formula for calculating a z-score when you are given a random.number of samples is z = (x-μ)/σ/√n
where x is the raw score
μ is the population mean
σ is the population standard deviation
n = random number of samples
Given a normal distribution with u = 75 and o = 40, if you select a sample of n = 16,
a) what is the probability that the sample mean is above 95? (4 d.p.) b)
= x = 95
Hence:
z = 95 - 75/40/√16
= 20/40/4
= 20/10
= 2
Probability value from Z-Table:
P(x<95) = 0.97725
P(x>95) = 1 - P(x<95) = 0.02275
The probability that the sample mean is above 95 to 4 decimal places = 0.0228
b) What is the value, of which there is 97.5% chance that a sample mean is less than that value?
97.5% chance = z score for the confidence interval = 1.96
Hence:
z = (x-μ)/σ/√n
1.96 = x - 75/40/√16
1.96 = x - 75/ 40/4
1.96 = x - 75/10
Cross Multiply
1.96 × 10 = x - 75
19.6 = x - 75
x = 19.6 + 75
x = 94.6
The value, of which there is 97.5% chance that a sample mean is less than that value is 94.6
I would go with A but I am not 100% sure so you may want to check however you can.
Answer: ![3ab\sqrt[3]{b^4}](https://tex.z-dn.net/?f=3ab%5Csqrt%5B3%5D%7Bb%5E4%7D)
Step-by-step explanation:
Given the following expression:
![\sqrt[3]{27a^3b^7}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27a%5E3b%5E7%7D)
You need to apply the Product of powers property, which states that:
Then, you can rewrite the expression as following:
![=\sqrt[3]{27a^3b^4b^3}](https://tex.z-dn.net/?f=%3D%5Csqrt%5B3%5D%7B27a%5E3b%5E4b%5E3%7D)
The next step is to descompose 27 into its prime factors:
Now you must substitute 
inside the given root. Then:
![=\sqrt[3]{3^3a^3b^4b^3}](https://tex.z-dn.net/?f=%3D%5Csqrt%5B3%5D%7B3%5E3a%5E3b%5E4b%5E3%7D)
You need to remember that, according to Radicals properties:
![\sqrt[n]{a^n}=a^{\frac{n}{n}}=a^1=a](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%5En%7D%3Da%5E%7B%5Cfrac%7Bn%7D%7Bn%7D%7D%3Da%5E1%3Da)
Therefore, the final step is to apply this property in order to finally get the expression is its simplest form. This is:
![=3^{\frac{3}{3}}a^{\frac{3}{3}}b^{\frac{4}{3}}b^{\frac{3}{3}}=3ab^{\frac{4}{3}}b=3ab\sqrt[3]{b^4}](https://tex.z-dn.net/?f=%3D3%5E%7B%5Cfrac%7B3%7D%7B3%7D%7Da%5E%7B%5Cfrac%7B3%7D%7B3%7D%7Db%5E%7B%5Cfrac%7B4%7D%7B3%7D%7Db%5E%7B%5Cfrac%7B3%7D%7B3%7D%7D%3D3ab%5E%7B%5Cfrac%7B4%7D%7B3%7D%7Db%3D3ab%5Csqrt%5B3%5D%7Bb%5E4%7D)
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