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Virty [35]
2 years ago
14

over the past five weeks, the average daily temperature in Wellington has dropped 40 degrees Fahrenheit. Write and evaluate ab e

xpression to show the average temperature change per week
Mathematics
1 answer:
Westkost [7]2 years ago
7 0
In five weeks, there are 35 days. So, the average drop in temperature per day is 40/35 = 8/7 degrees per week. Then in 1 week, 8/7 degrees per day * 7 days per week = 8 degrees per week.Therefore there are 8 degrees drop of temperature in 1 week.
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A taxi charges a flat rate of $3.00 plus $1.50 per mile. If Xander has $45.00, which inequality represents m, the distances in m
son4ous [18]

Answer:

  m less-than-or-equal-to 28

Step-by-step explanation:

Xander's charge for m miles will be (3 +1.50m). He wants this to be no more than $45, so ...

  3 +1.50m ≤ 45

  1.50m ≤ 42 . . . . . . subtract 3

  m ≤ 28 . . . . . . . . . .divide by 1.5

7 0
2 years ago
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Miguel wrote the predicted and residual values for a data set using the line of best fit y = 1.82x – 4.3. He left out two of the
Dmitry_Shevchenko [17]

Answer:

c

Step-by-step explanation:

i think it was c

5 0
2 years ago
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Determine whether each of the following functions is a solution of Laplace's equation uxx + uyy = 0. (Select all that apply.) u
Naddika [18.5K]

Answer with Step-by-step explanation:

We are given that Laplace's equation

u_{xx}+u_{yy}=0

We have to determine given function is  solution of given laplace's equation.

If a  function is solution of given Laplace's  equation then  it satisfy the solution.

1.u=e^{-x}cosy-e^{-y}cosx

Differentiate w.r.t x

Then, we get

u_x=-e^{-x}cosy+e^{-y}sinx

Again differentiate w.r.t x

u_{xx}=e^{-x}cosy+e^{-y}cosx

Now differentiate u w.r.t y

u_y=-e^{-x}siny+e^{-y}cosx

Again differentiate w.r.t y

u_{yy}=-e^{-x}cosy-e^{-y}cosx

Substitute the values in given Laplace's equation

e^{-x}cosy+e^{-y}cosx-e^{-x}cosy-e^{-y}cosx=0

Hence, given function is a solution of given Laplace's equation.

2.u=sinx coshy+cosx sinhy

Differentiate w.r.t x

u_x=cosx coshy-sinx sinhy

Again differentiate w.r.t x

u_{xx}=-sin x coshy-cosxsinhy

Now, differentiate u w.r.t y

u_y=sinx sinhy+cosx coshy

Again differentiate w.r.t y

u_{yy}=sinx coshy+cosx sinhy

Substitute the values then we get

-sinx coshy-cosxsinhy+sinxcoshy+cosx sinhy=0

Hence, given function is a solution of given Laplace's equation.

4 0
2 years ago
What is StartFraction 11 Over 12 EndFraction divided by one-third? A fraction bar labeled 1. Under the 1 are 3 boxes labeled one
Sav [38]

Answer:

<h2>2 and three-fourths </h2>

Step-by-step explanation:

Given the expression \frac{11}{12}/\frac{1}{3}, the equivalent expression can be gotten as shown;

= \frac{11}{12}/\frac{1}{3}\\= \frac{11}{12}*\frac{3}{1}\\  = \frac{11}{4} \\= 2+\frac{3}{4}\\ = 2\frac{3}{4}

2 and three-fourth therefore gives the required expression

8 0
2 years ago
Read 2 more answers
Turkey sandwiches cost $2.50 and veggie wraps cost $3.50 at a snack stand. Ben has sold no more than $30 worth of turkey sandwic
grigory [225]

<u>Answer:</u>

The maximum number of turkey sandwiches Ben could have sold is 6.

<u>Step-by-step explanation:</u>

We are given that turkey sandwiches cost $2.50 and veggie wraps cost $3.50 at a snack stand.

Given the information, we are to find the maximum value of turkey sandwiches Ben could have sold.

2 . 5 0 x + 3 . 5 0 y \leq 3 0

Number of veggie wraps sold (y) = 4

2.50x + 3.50(4) <   30

2.50x + 14          <   30

<u>           - 14               -14 </u>

2.50x                   <   16

x

x

The maximum number of turkey sandwiches Ben could have sold is 6.

4 0
2 years ago
Read 2 more answers
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