Gabriela needs to sell 4 more cups of coffee to make a profit of $75.
She sells 90 cups and makes $0.80 profit on each cup. That equals $72 profit.
90 x $0.80= $72
She wants to make $75 profit.
$75 - $72 = $3 profit short for the day
$3/$0.80 = 3.75 cups of coffee short so to make her profit she must sell a total of 94 cups of coffee for the day or an additional 4 cups.
Answer:
We can infer a cause-and-effect relationship because multiple variables were included.
Step-by-step explanation:
The multiple attributes for the divorced ones are
1) less physically active
2) an unhealthy weight,
3) smokers.
The attribute showing the % of the married is
1) death
So when we compare the two groups married and divorced we see different variables are involved in evaluating the percentage.
This shows a cause and effect involving multiple variables.
In cause and effect one variable is dependent and the other is independent.
The cause is the independent variable and effect is the dependent variable.
CAUSE EFFECT
Married Death
Divorced 1) less physically active
2) an unhealthy weight,
3) smokers.
Answer:

Step-by-step explanation:
Given:
The given function in terms of 'a' is given as:

In order to determine
, we need to make
equal to 'x' and find the value of 'a'. Therefore,

Now, plug in the value of 'a' on both sides, we get:

Therefore, the expression for the function in terms of 'x' is:

Answer:
1) The probability that ten students in a class have different birthdays is 0.883.
2) The probability that among ten students in a class, at least two of them share a birthday is 0.002.
Step-by-step explanation:
Given : Assume there are 365 days in a year.
To find : 1) What is the probability that ten students in a class have different birthdays?
2) What is the probability that among ten students in a class, at least two of them share a birthday?
Solution :

Total outcome = 365
1) Probability that ten students in a class have different birthdays is
The first student can have the birthday on any of the 365 days, the second one only 364/365 and so on...

The probability that ten students in a class have different birthdays is 0.883.
2) The probability that among ten students in a class, at least two of them share a birthday
P(2 born on same day) = 1- P( 2 not born on same day)
![\text{P(2 born on same day) }=1-[\frac{365}{365}\times \frac{364}{365}]](https://tex.z-dn.net/?f=%5Ctext%7BP%282%20born%20on%20same%20day%29%20%7D%3D1-%5B%5Cfrac%7B365%7D%7B365%7D%5Ctimes%20%5Cfrac%7B364%7D%7B365%7D%5D)
![\text{P(2 born on same day) }=1-[\frac{364}{365}]](https://tex.z-dn.net/?f=%5Ctext%7BP%282%20born%20on%20same%20day%29%20%7D%3D1-%5B%5Cfrac%7B364%7D%7B365%7D%5D)

The probability that among ten students in a class, at least two of them share a birthday is 0.002.