A rectangular parcel of land is 70 ft longer than it is wide. Each diagonal between opposite corners is 130 ft. What are the dim
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Answer:
1) 15cm
2) left projection/h = h/right projection
Step-by-step explanation:
Question:
1) The projections of the legs of a right triangle on the hypotenuse have lengths of 9 cm and 25 cm. Find the length of the height at the top of the right angle.
2) In a right triangle the length of the hypotenuse is 34 cm, and the lengths of the projections of the legs on the hypotenuse are directly proportional to the numbers 0, (6) and 0.75. Calculate the length of the height corresponding to the hypotenuse.
Solution
1) The length of the height of a right angle triangle is also called the altitude.
Since there are no diagrams in the question, I sent a diagram of the right angle as an attachment to the solution.
The projections of the legs are 25cm and 9cm.
Hence, the longer projection length AD = 25cm and the shorter projection length DB = 9cm
In a right triangle, the altitude (height) drawn from the right angle to the hypotenuse divides the hypotenuse into two segments. The length of the altitude is the
geometric mean of these two segments (the two projections) and it's given by:
left projection/h = h/right projection
AD/h = h/DB
25/h = h/9
Cross multiply
h^2 = 25×9
h =√225 = 15cm
The length of the height at the top of the triangle = 15cm
2) Length of hypotenuse = 34
From the question, the lengths of the projections of the legs on the hypotenuse are directly proportional to the numbers 0, (6) and 0.75.
There is an error with the figures because the sum of the length of the projection of the legs should be equal to the hypotenuse but it isn't in this case.
To calculate the length of the height corresponding to the hypotenuse, we would use the same formula above.
left projection/h = h/right projection
To find each leg using question 1 above, each leg of the triangle is the mean proportional between the hypotenuse and the part of the hypotenuse directly below the leg.
Hypotenuse =34cm
Hyp/leg = leg/part
To find leg y, part for leg y = 25cm
34/y = y/25
y^2 = 34×25 = 850
y = √850 = 29.2cm
To find leg x, part for leg x = 9cm
34/y = y/9
y^2 = 34×9 = 306
y = √306 = 17.5cm
We will traduce the sentences into equations.
Let x be the number of hours in the first job, and y be the number of hours in the second job.
Then the equations are:
The above system has many solution, we can select for example:
x = 1, y = 16. So we can work one hour at the first job and 16 hour at the second job.
Let x be the number of hours in the first job, and y be the number of hours in the second job.
Then the equations are:
The above system has many solution, we can select for example:
x = 1, y = 16. So we can work one hour at the first job and 16 hour at the second job.
Answer:
20.78feet
Step-by-step explanation:
The question made us to understand that the man is standing and also there is angle of elevation, then we need to draw a right triangle having a base equal to 36 feet with an angle from the base to the top of the pole which is 30 degrees.
tan= opposite side / adjacent side
Let height of the pole =h
Tan(30)= h/36
But tan 30degree= 1/√3
h= 36 × 1/√3
h= 20.78feet
Therefore, the height of the pole= 20.78feet
CHECK THE ATTACHMENT FOR DETAILED FIGURE
