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Tpy6a [65]
2 years ago
6

Suppose that a 10-Mbps wireless station is transmitting 50-byte frames one immediately after the other.

Computers and Technology
2 answers:
Andre45 [30]2 years ago
7 0
8 bits = 1 byte

10 Mbps = 10/8 M bytes per second

1 frame = 50 bytes

Frame rate = 10 M / (8 x 50) =  10 M / 400 = <em>25,000 frames per second</em>

========================

If each frame has an error probability of 0.004, then (0.004 x 25,000) = 100 frames per second are damaged.

1 hour = 3,600 seconds.

100 damaged frames per second = (100 x 3,600) = <em>360,000 damaged frames per hour.</em>
LenaWriter [7]2 years ago
6 0
There are 1'000'000 Bytes in a Megabyte. In 10 Megabytes there are 10'000'000 bytes. So if it were transmitting 1-byte frames then the answer would be 10'000'000 frames. However this is not the case, because it is transmitting 50-byte frames, so we must divide 10'000'000 by 50.

Therefore, the answer to part (i) is: 200'000 Frames/second

If there are 200'000 Frames/second, then there are 12'000'000 Frames/hour (we get that by multiplying 200'000 by 60)

If the probability of a damaged frame is 0.004, then (multiplying 0.004 by 12'000'000) we get (ii) 48'000 Damaged Frames/hour
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def string_finder(target,search): #function that takes two parameters i.e. target string and a search string

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#returns "not found"

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Explanation:

The program can also be written in by using string methods.

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           return "End" #if above elif condition it true return End

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           return "Middle"  #if above elif condition it true return End

       else:  #if none of the above conditions is true then returns Not Found

           return "Not Found"

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