The below code will help you to solve the given problem and you can execute and cross verify with sample input and output.
#include<stdio.h>
#include<string.h>
int* uniqueValue(int input1,int input2[])
{
int left, current;
static int arr[4] = {0};
int i = 0;
for(i=0;i<input1;i++)
{
current = input2[i];
left = 0;
if(current > 0)
left = arr[(current-1)];
if(left == 0 && arr[current] == 0)
{
arr[current] = input1-current;
}
else
{
for(int j=(i+1);j<input1;j++)
{
if(arr[j] == 0)
{
left = arr[(j-1)];
arr[j] = left - 1;
}
}
}
}
return arr;
}
Answer:
See the components in explaination
Explanation:
In order to make it as IPv6, few key components should be supported, those components are given below:
The infrastructure must support the enhanced protocol StateLess Address Auto-Configuration (SLAAC).
Static addressing with DHCPv6, dynamic addressing with DHCPv6 and SLAAC are the methods used to configure the IPv6. The network administrator should able to understand and implement the IPv6 through the DHCPv6.
Other than the implementation, working of IPv4 and IPv6 are same. Therefore, the administrator need not to learn new information for its working.
As the IPv6 address length is 128-bit and purpose is for everything on line to have an IP address. It must allow the internet to expand faster devices to get internet access quickly.
The DHCPv6 is not supported by all windows. Therefore, network administrator should check the corresponding Operating system (OS) would support the DHCPv6 for IPv6.
The network administrator must have good knowledge and skills on the IPv6.
The above mentioned key components should be verified by the network administrator in order to support for IPv6 project with DHCPv6.
For the answer to the question above asking, what h<span>ybrid processors that can process 32 bits or 64 bits are known by what term?
I think you are referring to the Chipset. and they are Manufactured by Intel and Advance Micro Devices (AMD). Intel's Pentium is the first one to have 32 bits and 64 bits of processors.</span>
Answer:
def sum_1k(M):
s = 0
for k in range(1, M+1):
s = s + 1.0/k
return s
def test_sum_1k():
expected_value = 1.0+1.0/2+1.0/3
computed_value = sum_1k(3)
if expected_value == computed_value:
print("Test is successful")
else:
print("Test is NOT successful")
test_sum_1k()
Explanation:
It seems the hidden part is a summation (sigma) notation that goes from 1 to M with 1/k.
- Inside the <em>sum_1k(M)</em>, iterate from 1 to M and calculate-return the sum of the expression.
- Inside the <em>test_sum_1k(),</em> calculate the <em>expected_value,</em> refers to the value that is calculated by hand and <em>computed_value,</em> refers to the value that is the result of the <em>sum_1k(3). </em>Then, compare the values and print the appropriate message
- Call the <em>test_sum_1k()</em> to see the result
Answer:
b. myString[:-5]
d. myString[-15:-5]
Explanation:
I believe you have a typo in d. It must be d. myString[-15:-5]
Slicing can be done:
myString[starting_index, stopping_index, step] (step is optional). If you do not specify the starting index, it will start from the 0 as in b. If you write a range that is not in the range, as in d, Python will replace it with either 0 or length of the string (In this case, it is replaced with 0 because the starting index must be smaller than stopping index)
a. myString[5] → This will give you the sixth character
b. myString[:-5] → This will give you the first five characters
c. myString[0:6] → This will give you the first six characters
d. myString-15:-5] → This will give you the first five characters
e. myString[0:10:2] → This will give you the first, third, fifth, seventh, and ninth characters
