Question

PLEASE HELP!! The amount a string stretches varies linearly with the mass applied to the spring, as can be seen in the video. In the video, with no additional mass, the hanger was 30.6 cm off the ground. With 150 grams of additional mass, the hanger was 16.2 cm off the ground.
A wooden block stretched the spring so the hanger was 24.8 cm off the ground. Determine the mass of the wooden block, to at least 1 decimal place.

Answer 1

Hello there!

d(m) = k*m
d(m) = 0.096 x m = 30.6 - 21.7
= (30.6 - 21.7)/0.096 = 92.7 grams
The answer is 92.7 to one decimal place

Hope This Helps You!
Good Luck :) 
 

Answer 2

Answer: The mass of the wooden block is 60.4 grams.

Step-by-step explanation:

Since we have given that

Without any additional mass , the hanger was 30.6 cm off the ground.

Let the function will be

f(m)=km, where k is a constant.

With 150 grams of additional mass, the hanger was 16.2 cm off the ground.

$f(150)=30.6-16.2\\\\f(150)=14.4\ cm$

So, our function becomes,

$f(150)=k\times 150\\\\14.4=k\times 150\\\\\frac{14.4}{150}=k\\\\k=0.096$

Now, our function becomes,

$f(m)=0.096m$

Now, the wooden block stretched the spring so, the hanger was 24.8 cm off the ground.

The mass of the wooden block is given by

$f(m)=0.096\times m=30.6-24.8\\\\0.096\times m=5.8\\\\m=\frac{5.8}{0.096}\\\\m=60.4\ grams$

Hence, the mass of the wooden block is 60.4 grams.