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ASHA 777 [7]
2 years ago
14

The disk drive is a secondary storage device that stores data by _____ encoding it onto a spinning circular disk.

Computers and Technology
1 answer:
Lisa [10]2 years ago
8 0
Magnetically





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(a) Show how to use (the Boolean formula satisfiability program) satisfiable num (and substitute) to find a satisfying assignmen
tia_tia [17]

Answer:

Check the explanation

Explanation:

(a)

# We need to try all options(TRUE/FALSE) of all the Variables

# to find the correct arrangement.

permutations <- permutate(0,1,n) [Find all permutions O(2^n)]

for permutation in permutations:

for X in variables:

if(permutation[i] == 1)

substitute(H,X,true)

else

substitute(H,X,false)

if(satisfiable(H)) return permutation

increment i

6 0
2 years ago
A network design engineer has been asked to design the IP addressing scheme for a customer network. The network will use IP addr
Lilit [14]

Answer:

192.168.30.0/24 is the network IP address and 192.168.30.255/24 is the IP broadcast  address.

Explanation:

The first IP (192.168.30.0/24) address of your subnet is the network address,  the last IP (192.168.30.255/24) address of your subnet is your broadcast address and the available usable IP addresses in your subnet are subnet size -2, because network address and broadcast address cannot be allocated to a system.

7 0
2 years ago
Show how the recursive multiplication algorithm computes XY, where X = 1234 and Y = 4321. Include all recursive computations.
lozanna [386]

Answer:

The result of recursive multiplication algorithm is 5332114 . Here karatsuba algorithm with recursive approach is used to compute XY where X = 1234 and Y = 4321.

Explanation:

The steps for karatsuba algorithm with recursive approach:

base case:

if(X<10) or (Y<10) then multiply X with Y

For example if X is 1 and Y is 2. Then XY = 1*2 = 2

Recursive case:

Now when the above if condition is not true then follow these steps to compute XY

Compute the size of numbers.

Notice that there are 4 digits in X i.e. 1 2 3 4 and a 4 digits in Y i.e. 4 3 2 1

So n = 4

Now divide the numbers in 2 parts as:

n/2 = 4/2 = 2

Since these are decimal numbers so we can write it as:

10^n/2

Now split the digits

X = 1234 is divided into 2 parts as:

12 and 34

Let a represent the first part and b represent the second part of X. So,

a = 12

b = 34

Y = 4321 is divided into 2 parts as:

43 and 21

Let c represent the first part and d represent the second part of Y. So,

c = 43

d = 21

Let multiplication reprsents the karatsuba recursive multiplication algorithm

Now recursively compute products of inputs of size n/2  

   multiplication (a, c)

   multiplication (b, d)

   multiplication (add(a, b), add(c, d))  

  Combine the above 3 products to compute XY  

As we know these decimal numbers have base 10 and X and Y are divided into two parts So X can be written as:

X = 10^{\frac{n}{2} }  a+b

Y can be written as:

Y = 10^{\frac{n}{2} }  c+d

Now compute XY as:

XY = (10^{\frac{n}{2} }  a+b) ( 10^{\frac{n}{2} }  c+d)

XY = 10^{\frac{2n}{2} }  ac + 10^{\frac{n}{2} }  ad +  10^{\frac{n}{2} }  bc + bd

     =  10^{n}  ac + 10^{\frac{n}{2} } (ad + bc) + bd

Now put the values of n = 4, a = 12, b = 34 , c = 43 and d = 21

      = 10⁴ (12*43) + 10² (12*21 + 34*43) + (34*21)

      = 10⁴ (516) + 10² (252 + 1462) + 714

      = 10000*516 + 100*1714 + 714

      = 5160000 + 171400 + 714

XY  = 5332114

Hence the karatsuba multiplication algorithm with recursive appraoch computes XY = 5332114

3 0
2 years ago
Enter an input statement using the input function at the shell prompt. When the prompt asks you for input, enter a number. Then,
Pavel [41]

Answer:

<u>Explanation:</u>

An input statement using the input function at the shell prompt is as follows:

If a prompt asks for a input, a number is to be added

num = input ('Number: ')

num = num + 1

print(num)

Explanation of results: This gives error at line num= num + 1 as cannot convert int object to str implicitly

8 0
2 years ago
In a system where Round Robin is used for CPU scheduling, the following is TRUE when a process cannot finish its computation dur
masha68 [24]

Answer:

B. The process will be terminated by the operating system.

Explanation:

When Round Robin is used for CPU scheduling, a time scheduler which is a component of the operating system is used in regulating the operation. A time limit is set for each of the processes to be run.

So, when a process fails to complete running before its time elapses, the time scheduler would log it off and return it to the queue. This queue is in a circular form and gives each of the processes a chance to run its course.

7 0
2 years ago
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