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2 years ago

Long division ×÷2=12 please help

2 answers:

7 0

This is not a long division problem.
This is an equation, where you need to find out what number 'x' is.
Here's how you do it:

The equation says x divided by 2 = 12

You can do anything you like to one side of the equation,
but whatever you decide to do there, you MUST immediately
do the same exact thing to the other side.

Look at the left side. The left side says "'x' divided by 2".
If we do just the opposite there, then we'll have 'x' all by
itself.
So let's multiply that side by 2.

Then, don't forget, we MUST also multiply the other side by 2 .

Here's how it goes:

'x' divided by 2 = 12

Multiply the left side by 2 : x

Multiply the right side by 2 : 24

Since we did the same thing
to both sides, they're still equal: x = 24 .

Look at that !
The question was "What number is 'x' ?"
and that's the answer ! 'x' is 24 !

rodikova [14]2 years ago

4 0

If x / 2 = 12, then all we need to do to find x is multiply 2 * 12.

2 * 12 = 24

That was easier than it should have been, right? =P

Well, let's check out work using long division.

12
___
2 / 24
-2 ↓
04
- 4
0

And the work checks out.

x = 24, where x <span>÷ 2 = 12.
Hope that helped =)</span>

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Jar A contains four liters of a solution that is 45% acid. Jar B contains five liters of a solution that is 48% acid. Jar C cont

castortr0y [4]

Answer:

k= 80%

Step-by-step explanation:

Jar A contains 4*0.45 L acid, and 4 L of a solution of acid.

Jar B contains 5*0.48 L acid., and 5 L of a solution of acid.

Jar C contains 1*k/100 = k/100 acid, and 1 L of a solution.

50% = 0.5

For jar A.

(2/3)*k/100 L acid is added to jar A.

Now jar A contains 4*0.45 L + (2/3)*k/100 L acid, and it has (4+2/3)L of a solution.

L solute/L solution = 0.5

[4*0.45 L + (2/3)*k/100 L]/(4+2/3)L = 0.5

[1.8 + (2k/300)]/[(12+2)/3] = 0.5

[1.8 + (2k/300)]/[14/3] = 0.5

[1.8 + (2k/300)]= 0.5*(14/3)

(2k/300) = 0.5*(14/3) - 1.8

2k = (0.5*(14/3) - 1.8)*300

k = (0.5*(14/3) - 1.8)*300/2 =80

k= 80%

We also can find k using jar B.

(1/3)k/100 L acid is added to jar B.

Now jar B contains 5*0.48 L+ (1/3)k/100 L acid, and it has (5+1/3) L of a solution.

L solute/L solution = 0.5

[5*0.48 L+ (1/3)k/100 L ]/(5+1/3)L= 0.5

[5*0.48 + (1/3)k/100 ]/(5+1/3)= 0.5

This equation also gives k=80%

Check.

We can check at least for jar A.

Jar A has 4L solution and 4*0.45=1.8 L acid.

2/3 L of the solution from jar C was added, and now we have 4 2/3 L of solution.

(2/3)* 80%= (2/3)*0.8 acid was added from jar C.

Now we have [1.8 +(2/3)*0.8] L acid in jar A.

L solute/L solution = [1.8 +(2/3)*0.8] L /(4 2/3) L = 0.5 or 50% as it is given that jar A has 50% at the end.

7 0

2 years ago

Trevor is analyzing a circle, y2 + x2 = 100, and a linear function g(x). Will they intersect?

lakkis [162]

Given a circle described by the equation:
$y^2+x^2=100$
and a function g(x) given by the table
$\begin{center}
\begin{tabular}{ |c |c |c }
 x & g(x) \\
 -1 & -22 \\
 0 & -20 \\
1 & -18 
\end{tabular}
\end{center}$

The function g(x) describes a straight line with the equation:
$\frac{y-y_1}{x-x_1} = \frac{y_2-y_1}{x_2-x_1} \\ \\ \frac{y-(-22)}{x-(-1)} = \frac{-20-(-22)}{0-(-1)} \\ \\ \frac{y+22}{x+1} = \frac{-20+22}{0+1} = \frac{2}{1} \\ \\ y+22=2(x+1)=2x+2 \\ \\ y=2x-20$

To check if the circle and the line intersects, we substitute the equation of the line into the equation of the circle to see if we have a real solution.
i.e.
$y^2+x^2=100 \\ \\ (2x-20)^2+x^2=100 \\ \\ 4x^2-80x+400+x^2=100 \\ \\ 5x^2-80x+300=0 \\ \\ x^2-16x+60=0 \\ \\ (x-6)(x-10)=0 \\ \\ x-6=0 \ or \ x-10=0 \\ \\ x=6 \ or \ x=10$

When x = 6, y = 2(6) - 20 = 12 - 20 = -8 and when x = 10, y = 2(10) - 20 = 20 - 20 = 0

Therefore, the circle and the line intersect at the points (6, -8) and (10, 0).

8 0

2 years ago

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What is the measure of Angle J K L? Triangle J K L . The exterior angle to angle K has a measure of 83 degrees. 83 degrees 97 de

nasty-shy [4]

Answer:

The measure of angle JKL is 97 degrees.

Step-by-step explanation:

Given:

A triangle JKL .

Measure of exterior angle K = 83 degrees

We have to find the measure of $\angle JKL$ .

In $(\triangle\ JKL)$ we see that the exterior angle is in linear pair with $\angle JKL$ .

Note:

Linear pair angles sum is 180 degree.

Let $\angle JKL$ be 'x' degrees .

So,

⇒ $x+83=180$

⇒ <em>Subtracting 83 from both sides.</em>

⇒ $x+83-83=180-83$

⇒ $x=180-83$

⇒ $x=97$ degrees

The measure of angle JKL in the triangle is of 97 degrees.

5 0

2 years ago

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A survey of one class at Pioneer Middle School found that 20 out of 30 students would spend $12 for a school t-shirt Suppose the

Virty [35]

$\frac{20}{30} = \frac{x}{600}$
600/30=20.
20*20=400.
Your answer is 400.

4 0

2 years ago

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In a day, Robin spends 6 hours at school, sleeps for 9 hours, plays for 3 hours, and spends the rest of the time doing other thi

slavikrds [6]

6hrs = school
9hrs = sleeps = 18hrs // 24hrs ----6hrs left
3hrs = plays

6hrs = other things

playing = 12.5% -- 3/24 3/24*100
other things = 25% -- 6/24 6/24*100

5 0

2 years ago

Read 2 more answers