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yanalaym [24]
1 year ago
7

Due to fire laws, no more than 720 people may attend a performance at metro auditorium. The balcony holds 120 people. There are

32 rows on the ground floor
Mathematics
1 answer:
valentina_108 [34]1 year ago
7 0
So what's the question?
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PLEASE HELPPPP , WILL GIVE BRAINLIESTTTTT
insens350 [35]

Answer:

80%

Step-by-step explanation:

What I did was just play with the numbers. But first, you'd multiply 6.00 time 3 because it's for the three people. Then just multiply 18 with .8 and bingo! The answer you get is 14.40, so the discount would be 80%

Hope this helps!

5 0
1 year ago
Read 2 more answers
A manageress earned £24,500 last year. This year she earns £25,235.
Korolek [52]

Answer:

Step-by-step explanation:

245000 last year

This year 25235

(y2 - y1) / y1)*100 = your percentage change

(where y1=start value and y2=end value)  

(( £25.235 - £24.500) / £24.500) * 100 = 0 %

There ain't no percentage change as there needs to be a bigger difference between the two numbers plus u should use the formula

7 0
1 year ago
In a circle with center C and radius 6, minor arc AB has a length of 4pi. What is the measure, in radians, of central angle ACB?
valina [46]
To solve this problem, we need to know that 
arc length = r θ  where θ is the central angle in radians.

We're given
r = 6 (units)
length of minor arc AB = 4pi
so we need to calculate the central angle, θ
Rearrange equation at the beginning,
θ = (arc length) / r = 4pi / 6 = 2pi /3

Answer: the central angle is 2pi/3 radians, or (2pi/3)*(180/pi) degrees = 120 degrees
8 0
1 year ago
Read 2 more answers
To plan the budget for next year a college must update its estimate of the proportion of next year's freshmen class that will ne
Naily [24]

Answer:

Null hypothesis:p\leq 0.35  

Alternative hypothesis:p > 0.35  

z=\frac{0.447 -0.35}{\sqrt{\frac{0.35(1-0.35)}{150}}}=2.491  

p_v =P(z>2.491)=0.0064  

So the p value obtained was a very low value and using the significance level assumed \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of applicants who request financial aid is significantly higher than 0.35

Step-by-step explanation:

Data given and notation

n=150 represent the random sample taken

X=67 represent the applicants who request financial aid

\hat p=\frac{67}{150}=0.447 estimated proportion of applicants who request financial aid

p_o=0.35 is the value that we want to test

\alpha represent the significance level

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion of applicants who request financial aid is higher than 0.35.:  

Null hypothesis:p\leq 0.35  

Alternative hypothesis:p > 0.35  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.447 -0.35}{\sqrt{\frac{0.35(1-0.35)}{150}}}=2.491  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(z>2.491)=0.0064  

So the p value obtained was a very low value and using the significance level assumed \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of applicants who request financial aid is significantly higher than 0.35

5 0
2 years ago
Vineet solved a system of equations by substitution. In his work, he substituted an expression for one of the variables and solv
mezya [45]
Vineet can conclude that:
B ) the system of equations does not have a solution.
10 0
1 year ago
Read 2 more answers
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