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Anna007 [38]
2 years ago
13

A hospital cafeteria has 20 20 tables. 65% 65 % of the tables have 6 6 chairs at each table. The remaining 35% 35 % of the table

s have 4 4 chairs at each table. Complete the model. Then complete the statements to find the total number of chairs in the hospital cafeteria.
Mathematics
2 answers:
Deffense [45]2 years ago
5 0

Answer:

106

Step-by-step explanation:

We calculate that 65% of 20 is 13, meaning 13 tables have 6 chairs while the remaining 7 only have four chairs.

We multiply 13*6 and 7*4 and add them to get the answer. 78+28 = 106, meaning there are 106 chairs in the cafeteria.

miss Akunina [59]2 years ago
4 0

\bf \begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{65\% of 20}}{\left( \cfrac{65}{100}\right)20}\implies 13


so, 13 of the 20 tables have 6 chairs each.

that means, the remaining 7 tables, have 4 chairs each.

13 * 6 = 78 chairs total for those 13 tables.

7 * 4 = 28 chairs total for the remaining 7 tables.

78 + 28, that's how many.

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The perimeter of a rectangle is 343434 units. Its width is 6.56.56, point, 5 units.
Andru [333]
This is annoying


the perimiter is 34 units
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ok.
perimiter=2(Length+Width)
P=2(L+W)
solve for L
distribute
P=2L+2W
minus 2W
P-2W=2L
divide by 2
\frac{P-2W}{2}=L

given that P=34 units and W=6.5 units
\frac{34-2(6.5)}{2}=L


the equation would be L=\frac{P-2W}{2} or L=\frac{P}{2}-W

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2 years ago
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Name the postulate or theorem you can use to prove ∆ABD ≅ ∆CBD.
lozanna [386]
Hey there!

Triangle CBD is congruent to triangle ABD. This means that BD is congruent to BD by reflexive property. You have two congruent angles, and one congruent side. This would be AAS theorem. The answer is D.

I hope this helps!
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2 years ago
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Find the distance from (4, −7, 6) to each of the following.
LenKa [72]

Answer:

(a) 6 units

(b) 4 units

(c) 7 units

(d) 9.22 units

(e) 7.21 units

(f) 8.06 units

Step-by-step explanation:

The distance d from one point (x₁, y₁, z₁) to another point (x₂, y₂, z₂) is given by;

d = √[(x₂ - x₁)² + (y₂ - y₁)² + (z₂ - z₁)²]

Now from the question;

<em>(a) The distance from (4, -7, 6) to the xy-plane</em>

The xy-plane is the point where z is 0. i.e

xy-plane = (4, -7, 0).

Therefore, the distance d is from <em>(4, -7, 6) </em> to <em>(4, -7, 0)</em>

d = √[(4 - 4)² + (-7 - (-7))² + (0 - 6)²]

d = √[(0)² + (0)² + (-6)²]

d = √(-6)²

d = √36

d = 6

Hence, the distance to the xy plane is 6 units

<em>(b) The distance from (4, -7, 6) to the yz-plane</em>

The yz-plane is the point where x is 0. i.e

yz-plane = (0, -7, 6).

Therefore, the distance d is from <em>(4, -7, 6) </em> to <em>(0, -7, 6)</em>

d = √[(4 - 0)² + (-7 - (-7))² + (6 - 6)²]

d = √[(4)² + (0)² + (0)²]

d = √(4)²

d = √16

d = 4

Hence, the distance to the yz plane is 4 units

<em>(c) The distance from (4, -7, 6) to the xz-plane</em>

The xz-plane is the point where y is 0. i.e

xz-plane = (4, 0, 6).

Therefore, the distance d is from <em>(4, -7, 6) </em> to <em>(4, 0, 6)</em>

d = √[(4 - 4)² + (-7 - 0)² + (6 - 6)²]

d = √[(0)² + (-7)² + (0)²]

d = √[(-7)²]

d = √49

d = 7

Hence, the distance to the xz plane is 7 units

<em>(d) The distance from (4, -7, 6) to the x axis</em>

The x axis is the point where y and z are 0. i.e

x-axis = (4, 0, 0).

Therefore, the distance d is from <em>(4, -7, 6) </em> to <em>(4, 0, 0)</em>

d = √[(4 - 4)² + (-7 - 0)² + (6 - 0)²]

d = √[(0)² + (-7)² + (6)²]

d = √[(-7)² + (6)²]

d = √[(49 + 36)]

d = √(85)

d = 9.22

Hence, the distance to the x axis is 9.22 units

<em>(e) The distance from (4, -7, 6) to the y axis</em>

The x axis is the point where x and z are 0. i.e

y-axis = (0, -7, 0).

Therefore, the distance d is from <em>(4, -7, 6) </em> to <em>(0, -7, 0)</em>

d = √[(4 - 0)² + (-7 - (-7))² + (6 - 0)²]

d = √[(4)² + (0)² + (6)²]

d = √[(4)² + (6)²]

d = √[(16 + 36)]

d = √(52)

d = 7.22

Hence, the distance to the y axis is 7.21 units

<em>(f) The distance from (4, -7, 6) to the z axis</em>

The z axis is the point where x and y are 0. i.e

z-axis = (0, 0, 6).

Therefore, the distance d is from <em>(4, -7, 6) </em> to <em>(0, 0 6)</em>

d = √[(4 - 0)² + (-7 - (0))² + (6 - 6)²]

d = √[(4)² + (-7)² + (0)²]

d = √[(4)² + (-7)²]

d = √[(16 + 49)]

d = √(65)

d = 8.06

Hence, the distance to the z axis is 8.06 units

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2 years ago
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Hitman42 [59]

Answer:

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Step-by-step explanation:

You can use f(15) = 40 to solve for C, then find f(0), the initial temperature.

  40 = f(15)

  40 = Ce^(-0.045·15) +14 = .50916C +14

  26 = .50916C

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Then f(0) is ...

  f(0) = 51.065·e^0 +14 = 65.065 ≈ 65

The initial temperature of the water was 65 degrees Fahrenheit.

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MaRussiya [10]

Answer:

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Step-by-step explanation:

The figure shows two congruent by HA theorem (they have congruent hypotenuses and a pair of congruent angles adjacent to the hypotenuses) triangles KLP and QNM.

A rigid transformation is a transformation which preserves lengths. Reflection, rotation and translation are rigit transformations.

If you reflect triangle KLP across the leg KP and translate it up so that point P coincides with point M , then the image of triangle KLP after these transformations will be triangle QNM.

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2 years ago
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