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Vsevolod [243]
2 years ago
14

Kristine has been getting many unsolicited emails from a particular address. She thinks that these emails may harm her computer.

What action should she take to automatically send such emails to a separate folder?
Computers and Technology
2 answers:
vovikov84 [41]2 years ago
3 0
Kristine should mark the messages as spam.
Lena [83]2 years ago
3 0

Since Kristine has been getting many unwanted emails which she did not sign up for, she might have to mark all these emails’ senders as spam so that any new emails from these senders would immediately be sent to the Spam folder.

These emails can be harmless but annoying, but it can also create unknown adverse effects later on when the email is opened. Never open the links available in these type of emails because they will certainly create damage to your computer or information.

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_____ computing refers to a computing environment that is always present, can feel our surroundings, and-based on who we are, wh
tensa zangetsu [6.8K]

Answer:

b. Contextual computing

Explanation:

Contextual computing -

In this method of computing , the hardware and the software collect and examine the data all by itself from the near by areas in order to make it presentable , is known as the method of contextual computing .

It is also known as the context - aware computing .

Hence , from the given information of the question , the correct term from the given options is b. Contextual computing .

4 0
2 years ago
Consider a router that interconnects three subnets: subnet 1, subnet 2, and subnet 3. suppose all of the interfaces in each of t
creativ13 [48]

Answer:

thank God for us you and keep hoping tougher than I thought it would be

4 0
2 years ago
Read 2 more answers
Which of the following is true about protected access?
goldenfox [79]

Answer:(A) Protected members may be accessed by methods in the same package or in a subclass, even when the subclass is in a different package.

Explanation:

Methods,constructors and variables, that are protected in superclass they can be only accessed by any class within the package of the protected members class and methods in the same package or they can be of a subclass or the subclasses that may be present in other package .

5 0
2 years ago
Suppose a host has a 1-MB file that is to be sent to another host. The file takes 1 second of CPU time to compress 50%, or 2 sec
kozerog [31]

Answer: bandwidth = 0.10 MB/s

Explanation:

Given

Total Time = Compression Time + Transmission Time

Transmission Time = RTT + (1 / Bandwidth) xTransferSize

Transmission Time = RTT + (0.50 MB / Bandwidth)

Transfer Size = 0.50 MB

Total Time = Compression Time + RTT + (0.50 MB /Bandwidth)

Total Time = 1 s + RTT + (0.50 MB / Bandwidth)

Compression Time = 1 sec

Situation B:

Total Time = Compression Time + Transmission Time

Transmission Time = RTT + (1 / Bandwidth) xTransferSize

Transmission Time = RTT + (0.40 MB / Bandwidth)

Transfer Size = 0.40 MB

Total Time = Compression Time + RTT + (0.40 MB /Bandwidth)

Total Time = 2 s + RTT + (0.40 MB / Bandwidth)

Compression Time = 2 sec

Setting the total times equal:

1 s + RTT + (0.50 MB / Bandwidth) = 2 s + RTT + (0.40 MB /Bandwidth)

As the equation is simplified, the RTT term drops out(which will be discussed later):

1 s + (0.50 MB / Bandwidth) = 2 s + (0.40 MB /Bandwidth)

Like terms are collected:

(0.50 MB / Bandwidth) - (0.40 MB / Bandwidth) = 2 s - 1s

0.10 MB / Bandwidth = 1 s

Algebra is applied:

0.10 MB / 1 s = Bandwidth

Simplify:

0.10 MB/s = Bandwidth

The bandwidth, at which the two total times are equivalent, is 0.10 MB/s, or 800 kbps.

(2) . Assume the RTT for the network connection is 200 ms.

For situtation 1:  

Total Time = Compression Time + RTT + (1/Bandwidth) xTransferSize

Total Time = 1 sec + 0.200 sec + (1 / 0.10 MB/s) x 0.50 MB

Total Time = 1.2 sec + 5 sec

Total Time = 6.2 sec

For situation 2:

Total Time = Compression Time + RTT + (1/Bandwidth) xTransferSize

Total Time = 2 sec + 0.200 sec + (1 / 0.10 MB/s) x 0.40 MB

Total Time = 2.2 sec + 4 sec

Total Time = 6.2 sec

Thus, latency is not a factor.

5 0
2 years ago
9.6 Code Practice: Question 1
worty [1.4K]

Answer:

  1. import java.util.Random;
  2. import java.util.Arrays;
  3. public class Main {
  4.    public static void main(String[] args) {
  5.        int n = 10;
  6.        int [] myArray = new int[n];
  7.        buildArray(myArray, n);
  8.        System.out.println(Arrays.toString(myArray));
  9.    }
  10.    public static void buildArray(int[] arr, int n){
  11.        for(int i=0; i < arr.length; i++){
  12.            Random rand = new Random();
  13.            arr[i] = rand.nextInt(90) +10;
  14.        }
  15.    }
  16. }

Explanation:

Firstly, create a method buildArray that take two inputs, an array and an array size (Line 12). In the method, use random nextInt method to repeatedly generate a two digit random number within a for loop that will loop over array size number of times (Line 13-15). The expression rand.nextInt(90) + 10 will generate digits between 10 - 99.

In the main program, call the build array method by using an array and array size as input arguments (Line 8). At last, print the array after calling the buildArray method (Line 9).

8 0
2 years ago
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