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Lynna [10]
2 years ago
3

One half of a number y is more than 22

Mathematics
2 answers:
pochemuha2 years ago
6 0

Answer:

Inequality: \frac{y}{2}>22

Solution: y>44

Step-by-step explanation:

We are supposed to write and solve an inequality for the given verbal description.

One half of a number y would be y divided by 2: \frac{y}{2}.

Since one half of a number y is more than 22, so we can set an inequality as:

\frac{y}{2}>22

Multiply both sides by 2:

\frac{y}{2}*2>22*2

y>44

Therefore, the solution to our given inequality is any value of y greater than 44.

jasenka [17]2 years ago
4 0
Set up the inequality first

.5y>22
y>44
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A machine that cuts corks for wine bottles operates in such a way that the distribution of the diameter of the corks produced is
Norma-Jean [14]

Answer:

A. P(x<3.85 or x>4.15)= P(x<3.85)+P(x>4.15) = 0.1336

Step-by-step explanation:

Working with an ordinary Normal Distribution of probability and trying to find the probabilities asked in it could be difficult, because there´s no easy method to find probabilities in a generic Normal Distribution (with mean μ=4 and STD σ=0.1). The recommended approach to this question is to use a process called "Normalize", this process let us translate the problem of any Normal Distribution to a Standard Normal Distribution (μ=0 and σ=1) where there´s easier ways to find probabilities in there. The "Normalization" goes as follows:

Suppose you want to know P(x<a) of the Normal Distribution you are working with:

P(x<a)=P( (x-μ)/σ < (a-μ)/σ )=P(z<b)   ( b=(a-μ)/σ )

Where μ is the mean and σ is the STD of your Normal Distribution. Notice P(z<b) now it´s a probability in a Standard Normal Distribution, now we can find it using the available method to do so. My favorite is a chart (It´s attached to this answer) that contains a lot of probabilities in a Standard Normal Distribution. Let´s solve this as an example

A. We want to find the probability of the cork being defective (P(x<3.85) + P(x>4.15)). Now we find those separated and, then, add them for our answer.

Let´s begin with P(x<3.85), we start by normalizing that probability:

P(x<3.85)= P( (x-μ)/σ < (3.85-4)/0.1 )= P(z<-1.5)

And now it´s time to use the chart, it works like this: If you want P(z<c) and the decimal expansion of c=a.bd... , then:

P(z<c)=(a.b , d)

Where (a.b , d) are the coordinates of the probability in the chart. Keep in mind that will only work with "<" (It won´t work directly with P(z>c)) and we will do some extra work in those cases.

P(z<-1.5) is in the coordinates (-1.5 , 0)

P(z<-1.5)= 0.0668

P(x<3.85)= 0.0668

Now we are looking for P(x>4.15), let´s Normalize it too:

P(x>4.15)=P( (x-μ)/σ < (4.15-4)/0.1 )=P(z>1.5)

But remember the chart only work with "<", so we need to use a property of probability:

P(z>1.5)= 1 - P(z<1.5)

Using the chart:

P(z<1.5)=0.9332                             (1.5 , 0)

P(z>1.5)= 1 - 0.9332

P(z>1.5)= 0.0668

P(x>4.15)= 0.0668

And our final answer will be:

P(x<3.85 or x>4.15)= P(x<3.85)+P(x>4.15) = 0.1336

4 0
2 years ago
Write a polynomial function, p(x) with degree 3 that has p(7)=0
MArishka [77]

Answer:

p (x) = x^{3} - 21x^{2}+ 147x - 343

is the required polynomial with degree 3 and p ( 7 ) = 0

Step-by-step explanation:

Given:

p ( 7 ) = 0

To Find:

p ( x ) = ?

Solution:

Given p ( 7 ) = 0 that means substituting 7 in the polynomial function will get the value of the polynomial as 0.

Therefore zero's of the polynomial is seven i.e 7

Degree : Highest raise to power in the polynomial is the degree of the polynomial

We have the identity,

(a -b)^{3} = a^{3}-3a^{2}b +3ab^{2} - b^{3}

Take a = x

        b = 7

Substitute in the identity we get

(x -7)^{3} = x^{3}-3x^{2}(7) +3x(7)^{2} - 7^{3}\\(x -7)^{3} = x^{3}-21x^{2} +147x - 343

Which is the required Polynomial function in degree 3 and if we substitute 7 in the polynomial function will get the value of the polynomial function zero.

p ( 7 ) = 7³ - 21×7² + 147×7 - 7³

p ( 7 ) = 0

p (x) = x^{3} - 21x^{2}+ 147x - 343

4 0
2 years ago
1. Natasha invests £250 in a building society account. At the end of the year her account is credited with 2% interest. How much
Kamila [148]

1. Natasha invests £250 in a building society account. At the end of the year her account is

credited with 2% interest. How much interest had her £250 earned in the year?

Solution: Interest = 2% of £250

= 2/100 x £250

 answer       = £5

2. Alan invests £140 in an account that pays r% interest. After the first year he receives £4.20 interest. What is the value of r, the rate of interest?

r/100 x £140 = £4.20

        r = 100 x 4.20 / 140

             = 420/140

           = 3%

So the interest rate is 3%

5 0
2 years ago
When the equation a – bx = cx + d is solved for x, the result is x = StartFraction a minus d Over b plus c EndFraction..
kiruha [24]

Answer:

x = -12/14 is the required solution for the given expression.

Step-by-step explanation:

Here, the given expression is:

5 – 6 x  = 8 x + 17

Now, here solving the expression for the value of x, we get:

5 – 6 x  = 8 x + 17

⇒ 5 -  17   = 8 x +  6 x

⇒- 12  = 14 x

or, x  = -12 / 14

Hence, x = -12/14 is the required solution for the given expression.

8 0
2 years ago
Read 2 more answers
Yoku is putting on sunscreen. He uses 2\text{ ml}2 ml2, start text, space, m, l, end text to cover 50\text{ cm}^250 cm 2 50, sta
Kaylis [27]

Answer:

13 Millilitres.

Step-by-step explanation:

Yoku uses 2ml to cover 50cm^2 of his skin.

He wants to know how many millilitres of sunscreen he will need to cover 325cm^2 of his body.

If Yoku covers 50cm^2 of his skin will 2ml

He will cover 1cm^2 of his skin with \frac{2}{50}ml of sunscreen.

Therefore:

To cover 325cm^2 of his body, he will use:

\frac{2}{50} X 325 ml\\=13ml

he would require 13 Millilitres.

7 0
2 years ago
Read 2 more answers
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