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2 years ago

15

There are 38 pockets on an american roulette wheel: 18 red, 18 black, and 2 green. if you were to randomly spin an american roul

ette wheel, what is the probability that it would land on a green pocket

1 answer:

Pavel [41]2 years ago

8 0

You have about 5.23% chance to land in a green pocket. You can find this by dividing 2/38 or the questioned amount by the total amount of options.

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A spherical ball just fits inside a cylindrical can that is 10 centimeters tall, with a diameter of 10 centimeters. Which expres

egoroff_w [7]

Check the picture below.

$\bf \textit{volume of a sphere}\\\\ V = \cfrac{4\pi r^3}{3}~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r = 5 \end{cases}\implies V=\cfrac{4\pi (5)^3}{3} \\\\\\ V=\cfrac{500\pi }{3}\implies V\approx 523.6$

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2 years ago

A $400,000 loan has monthly interest-only payments of $2,600. What is the annual interest rate? 6.5, 7.2, 7.4 or 7.8?

Amiraneli [1.4K]

(annual interest)/(loan amount) = interest rate
(12×$2,600)/$400,000 = .078 = 7.8% . . . . annual interest rate

6 0

2 years ago

Read 2 more answers

For circle O, and m∠ABC = 55°. In the figure, ∠_____ and ∠____ have measures equal to 35°.

luda_lava [24]

Answer:

In the figure ∠ABO and ∠BCO have measures equal to 35°.

Step-by-step explanation:

<u><em>The complete question is</em></u>

For circle O, m CD=125° and m∠ABC = 55°

In the figure<____, (AOB, ABO, BOA) and <_____ (BCO, OBC,BOC) have measures equal to 35°

The picture in the attached figure

step 1

Find the measure of angle COB

we know that

$m\angle COB=arc\ CD$ ----> by central angle

we have

$arc\ CD=125^o$

therefore

$m\angle COB=125^o$

step 2

we know that

AB is a tangent to the circle O at point A

so

ABC and ABO are right triangles

In the right triangle ABC

Find the measure of angle BCA

Remember that

$m\angle BCA+m\angle\ ABC=90^o$ ---> by complementary angles in a right triangle

we have

$m\angle ABC=55^o$

substitute

$m\angle BCA+55^o=90^o$

$m\angle BCA=90^o-55^o=35^o\\$

step 3

In the triangle BCO

Find the measure of angle CBO

we know that

$m\angle CBO+m\angle COB+m\angle BCO=180^o$ ---> the sum of the interior angles in any triangle must be equal to 180 degrees

we have

$m\angle COB=125^o$

$m\angle BCO=m\angle BCA=35^o$ -----> have measure equal to 35 degrees

substitute

$m\angle CBO+125^o+35^o=180^o$

$m\angle CBO=180^o-160^o=20^o$

step 4

Find the measure of angle ABO

In the right triangle ABO

we know that

$m\angle ABC=m\angle CBO+m\angle ABO$ ----> by angle addition postulate

we have

$m\angle ABC=55^o$

$m\angle CBO=20^o$

substitute

$55^o=20^o+m\angle ABO$

$m\angle ABO=55^o-20^o=35^o$ ----> have measure equal to 35 degrees

therefore

In the figure ∠ABO and ∠BCO have measures equal to 35°.

3 0

2 years ago

If mJI = (3x+2)°, mHLK = (15x-36)°, and m∠HML = (8x-1)°, find mHLK

Gala2k [10]

Answer:

The value of mHLK will be "(204)°".

Step-by-step explanation:

The given values are:

mJI = (3x+2)°

mHLK = (15x-36)°

and,

m∠HML = (8x-1)°

then,

mHLK = ?

Now,

By using chord-chord formula of angle, we get

$mHMK=\frac{1}{2}(mJL+mHLK)$

On putting the values in the above formula, we get

⇒ $(8x-1)=\frac{1}{2}(15x-36+3x+2)$

On applying cross-multiplication, we get

⇒ $2(8x-1)=18x-34$

⇒ $16x-2=18x-34$

On subtracting "18x" from both sides, we get

⇒ $16x-2-18x=18x-34-18x$

⇒ $-2x-2=-34$

On adding "2" both sides, we get

⇒ $-2x=-34+2$

⇒ $-2x=-32$

⇒ $x=\frac{32}{2}$

⇒ $x=16$

On putting the value of "x" in mHLK = (15x-36)°, we get

⇒ (15x-36)° = (15×16-36)°

⇒ = (240-36)°

⇒ = (204)°

So that mHLK = (204)°

4 0

2 years ago

Trains A and B, 200 km apart on the same straight track, travel at speeds of 50 km/hr and 65 km/hr respectively. At the end of 1

Gwar [14]

Answer:

Ok, at the beginning the distance between the trains is 200km:

IPa(0s) - P(0s)I = 200km.

where Pa is the position of train A, and Pb is the position of train B.

Now, the speed of train A is:

Sa = 50km/h

Sb = 65km/h

Now, remember the relation:

Distance = Speed*time.

So, in one hour, the displacement of train A is:

Distance = 50km/h*1h = 50km

The displacement of train B is:

distance = 65km/h*1h = 65km.

Now, if at the beginning train A is 200km ahead of train B, then we have:

Pa - Pb = (Pa(0s) + 50km) - (Pb(0s) + 65km)

= (Pa(0s) - Pb(0s)) + (50km - 65km) = 200km - 15km = 185km.

Now, if train B was 200km ahead of train A, we have:

Pb - Pa = (Pb(0s) + 65km) - (Pa(0s) - 50km) =

(Pb(0s) - Pa(0s)) + (65km - 50km) = 200km + 15km = 215km

4 0

2 years ago