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bearhunter [10]
2 years ago
12

jessie uses 20 liters of gasoline to travel 200kilometers, how many liters of gasoline will he use on a trip of 700 kilometer?

Mathematics
2 answers:
VikaD [51]2 years ago
8 0

Answer: He will use 70 liters of gasoline on a trip of 700 kilometer.

Step-by-step explanation:

Given : Jessie uses 20 liters of gasoline to travel 200 kilometers.

We assume that the rate of consumption of gasoline is contant.

By UNITARY METHOD, the amount of gasoline required for 1 kilometer distance = \dfrac{20}{200}=\dfrac{1}{10} liter

Now, the amount of gasoline required for 700 kilometer distance = 700\times\dfrac{1}{10}=70 liters

Hence, He will use 70 liters of gasoline on a trip of 700 kilometer.

Damm [24]2 years ago
6 0
20:200
?:700
200×3.5=700
20×3.5=?
?=70
He can use 70 liters of gasoline on a trip of 700km
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Answer:

The correct option is  A

Step-by-step explanation:

From the question we are told that

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     The level of significance is \alpha  =  5\%  = 0.05

      The sample data is  9.0, 7.3, 6.0, 8.8, 6.8, 8.4, and 6.6 pounds

The Null hypothesis is H_o  :  \mu =  6.6

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      \=x =  \frac{\sum x_i }{n}

substituting values

      \=x =  \frac{9.0 +  7.3 +  6.0+ 8.8+ 6.8+ 8.4+6.6 }{7}

      \=x =  7.5571

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           \sigma  =  \sqrt{\frac{\sum  [ x -  \= x ]}{n} }

substituting values

          \sigma  =  \sqrt{\frac{  [ 9.0-7.5571]^2 + [7.3 -7.5571]^2 + [6.0-7.5571]^2 + [8.8- 7.5571]^2 + [6.8- 7.5571]^2 + [8.4 - 7.5571]^2+ [6.6- 7.5571]^2 }{7} }\sigma =  1.1774

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            t  =  \frac{\= x - \mu }  { \frac{\sigma }{\sqrt{n} } }

substituting values

           t  =  \frac{7.5571  - 6.6  }  { \frac{1.1774 }{\sqrt{7} } }

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