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erik [133]
2 years ago
3

What is the perimeter of the rectangle shown on the coordinate plane, to the nearest tenth of a unit? a.13.4 units b.17.9 units

c.26.8 units d.40.0 units

Mathematics
1 answer:
zalisa [80]2 years ago
7 0
To calculate the perimeter, consider each side separately. Since this is a rectangle, you have 2 pairs of sides of equal length, so you just have to calculate the length of one of each pair of sides and then double each and add them to find the perimeter.

Top side: If you look carefully, this side is really the hypotenuse of a triangle that is 4 units tall and 8 units long. Using the Pythagorean Theorem, you can calculate the length of the hypotenuse to be 8^2 + 4^2 = c^2 --> c = 8.9

Left side: Just like the top side, this side is the hypotenuse of a triangle that is 4 units tall and 2 units long. Pythagoras again: 4^2 + 2^2 = c^2 --> c = 4.5

Since you have two of each side that are the same length, double each and add for the final perimeter: 8.9*2 + 4.5*2 = 26.8
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A population consists of the following five values: 1, 3, 4, 4, and 6. List all samples of size 2 from left to right without rep
aniked [119]

Answer:

The sample of sizes 2 and their mean are given below.

Step-by-step explanation:

The population consist of  5 values, S = {1, 3, 4, 4, 6}.

The number of samples of size 2 (without replacement) that can be formed from these 5 values is:

{5\choose 2}=\frac{5!}{2!(5-2)!} =10

Th formula to compute the mean is:

\bar x=\frac{1}{n}\sum x_{i}

List the 10 samples and their mean as follows:

<u>Sample</u>                       <u>Mean</u>

(1, 3)                    \bar x=\frac{1}{2}[1+3]=\frac{4}{2}=2.0

(1, 4)                    \bar x=\frac{1}{2}[1+4]=\frac{5}{2}=2.5

(1, 4)                    \bar x=\frac{1}{2}[1+4]=\frac{5}{2}=2.5

(1, 6)                    \bar x=\frac{1}{2}[1+6]=\frac{7}{2}=3.5

(3, 4)                   \bar x=\frac{1}{2}[3+4]=\frac{7}{2}=3.5

(3, 4)                   \bar x=\frac{1}{2}[3+4]=\frac{7}{2}=3.5

(3, 6)                   \bar x=\frac{1}{2}[3+6]=\frac{9}{2}=4.5

(4, 4)                   \bar x=\frac{1}{2}[4+4]=\frac{8}{2}=4.0

(4, 6)                   \bar x=\frac{1}{2}[4+6]=\frac{10}{2}=5.0

(4, 6)                   \bar x=\frac{1}{2}[4+6]=\frac{10}{2}=5.0

8 0
2 years ago
A rectangle that had the perimeter of 70 and the area of 250 has enlarged; its sides became twice as long. what is the new area
aliya0001 [1]
The perimeter of the original rectangle is:
 P = 2w + 2l = 70
 The area of the original rectangle is:
 A = w * l = 250
 Then, by modifying the length of its sides we have:
 Perimeter:
 P '= 2 (2w) +2 (2l)
 Rewriting:
 P '= 2 (2w + 2l)
 P '= 2P
 P '= 2 (70)
 P '= 140
 Area:
 A '= (2w) * (2l)
 Rewriting:
 A '= (2) * (2) (w) * (l)
 A '= 4 * w * l
 A '= 4 * A
 A '= 4 * 250
 A '= 1000
 Answer:
 
the new area and the new perimeter are:
 
P '= 140
 
A '= 1000
3 0
2 years ago
What is the range of the function represented by the graph?
sergejj [24]
The correct answer is C. y> 1
4 0
2 years ago
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20% of the tickets sold at a water park were adult tickets. If the park sold 55 tickets in all,how many did it sell?
djyliett [7]

Answer:

11 adult tickets

Step-by-step explanation:

I guess you want the number of adult tickets sold.

That is 20% of 55

= 0.20*55

= 11 (answer)

8 0
2 years ago
Read 2 more answers
WILL GIVE BRAINLIEST ANSWER!!
Natasha2012 [34]
Check the picture below.

now, bear in mind that, there are 60minutes in 1 degree, so 23' is just 23/60 degrees or about 0.38 degrees.

and 29' is just 29/60 degrees or about 0.48 degrees.

so 16°23' is about 16.38°, and 49°29' is about 49.48°

\bf tan(16.38^o)=\cfrac{200}{a+b}\implies a+b=\cfrac{200}{tan(16.38^o)}&#10;\\\\\\&#10;\boxed{b=\cfrac{200}{tan(16.38^o)}-a}&#10;\\\\\\&#10;tan(49.48^o)=\cfrac{200}{b}\implies \boxed{b=\cfrac{200}{tan(49.48^o)}}\\\\&#10;-------------------------------\\\\&#10;\cfrac{200}{tan(49.48^o)}=\cfrac{200}{tan(16.38^o)}-a\\\\\\a=\cfrac{200}{tan(16.38^o)}-\cfrac{200}{tan(49.48^o)}

make sure your calculator is in Degree mode.

4 0
2 years ago
Read 2 more answers
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