All categories

2 years ago

On the first play of the game, the Wildcats gained 8 yd. What integer represents a gain of 8 yd?

2 answers:

5 0

From 0:

A positive number would mean you gained more numbers than lost numbers.
A negative number would mean you lost more numbers than gained numbers.

Therefore, positive is a gain.

So a gain of 8 yards would be positive 8, or just 8.

Hope this helps! :)

vesna_86 [32]2 years ago

4 0

The integer 8 represents a gain of 8 yards.

You might be interested in

A turtle swims at a speed of 1584 meters per hour. A girl swims at a speed of 1380 millimeters per second how much faster does t

d1i1m1o1n [39]

The turtle swims faster. In fact, the turtle swims 812 cm/min faster.

5 0

2 years ago

Read 2 more answers

The random variable X is exponentially distributed, where X represents the waiting time to see a shooting star during a meteor s

faltersainse [42]

Answer:

The parameters of the exponential distribution is 0.0133.

Step-by-step explanation:

Exponential distribution is a continuous probability distribution.

The density function of exponential distribution is,

$f _{X}(x)=\theta \cdot e^{-\theta\cdot x},\ x\geq 0$

Here the parameter θ is the reciprocal of the mean of the random variable <em>X</em>.

The random variable <em>X</em> has an average value of 75 seconds.

Compute the parameters of the exponential distribution as follows:

$\theta=\frac{1}{\mu}\\\\$

$=\frac{1}{75}\\\\=0.013333333333\\\\\approx 0.0133$

Thus, the parameters of the exponential distribution is 0.0133.

3 0

1 year ago

What is the following product? RootIndex 3 StartRoot 16 x Superscript 7 Baseline EndRoot times RootIndex 3 StartRoot 12 x Supers

Nadya [2.5K]

Answer:

$4x^5\sqrt[3]{3x}$

Step-by-step explanation:

I'm not sure I understand the problem, but I think it's this:

$\sqrt[3]{16x^7} \times \sqrt[3]{12x^9} =$

$= \sqrt[3]{16 \times 12 \times x^{16}}$

$= \sqrt[3]{192 \times x^{15} \times x}$

$= \sqrt[3]{64 \times 3 \times (x^5)^3 \times x}$

$= \sqrt[3]{4^3 \times 3 \times (x^5)^3 \times x}$

$= 4x^5\sqrt[3]{3x}$

8 0

2 years ago

Martin chose two of the cards below. When he found the quotient of the numbers, his answer was -16/9. Write the division problem

Sveta_85 [38]

Answer:

The required division problem he must solve is:

$\frac{2}{3} \div \frac{-3}{8} =\frac{2}{3}\times\frac{-8}{3}=\frac{-16}{9}$

Step-by-step explanation:

Consider the provided information.

Martin chose two of the cards below. When he found the quotient of the numbers, his answer was -16/9.

As we know that the quotient of the number is a negative number.

Therefore, the sign of both numbers must be different,

Thus we can concluded he must select $\frac{2}{3}$ as one of the card, so that product is a negative number.

Let the selected card be x.

$\frac{2}{3} \div x =\frac{-16}{9}\\\\x=\frac{2}{3}\div\frac{-16}{9}\\\\x=\frac{2}{3}\times\frac{-9}{16}\\\\x=\frac{-3}{8}$

Hence, the two cards should be $\frac{2}{3}$ and $\frac{-3}{8}$

The required division problem he must solve is:

$\frac{2}{3} \div \frac{-3}{8} =\frac{2}{3}\times\frac{-8}{3}=\frac{-16}{9}$

3 0

2 years ago

RS=2x-8, ST= 11, RT= x+10

swat32

Answer:

X=7 ST=11 RT=17

Step-by-step explanation:

RT=RS+ST. RS= 2(7)-8. ST=11

X+10=2x-8+11. =14-8=6. RT= x+10

X+10=2x+3. RS=6. 7+10=17

10=x+3. RT=17

X=7

4 0

2 years ago