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Mademuasel [1]
2 years ago
6

Find the given limit lim(x,y)→(a,a)x4−y4x2−y2=lim(x,y)→(a,a) (x^4−y^4)/(x2−y2)= here aa is a constant. (find the limit assuming

x≠y)
Mathematics
1 answer:
Aliun [14]2 years ago
7 0
If x\neq y, then we can write

\dfrac{x^4-y^4}{x^2-y^2}=\dfrac{(x^2-y^2)(x^2+y^2)}{x^2-y^2}=x^2+y^2

and since this is continuous for all x\neq y, the limit as (x,y)\to(a,a) will be

\displaystyle\lim_{(x,y)\to(a,a)}\frac{x^4-y^4}{x^2-y^2}=\lim_{(x,y)\to(a,a)}(x^2+y^2)=2a^2
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Suppose flaws (cracks, chips, specks, etc.) occur on the surface of glass with density of 3 per square meter. What is the probab
DiKsa [7]

Answer:

0.047

Step-by-step explanation:

Given that poisson distribution with mean m, for 0.5 square meter =1.5

Then the formula for finding the probability =

P[k] = (e^-m * m^k) k!

Hence we have

P[4] =[ (e^-1.5) * (1.5^4)] ÷ 4 * 3 * 2 * 1

= (0.2231301601 * 5.0625) ÷ 24

=( 1.12944375) ÷24

= 0.04706

≈ 0.047

Hence, the final answer is 0.047

8 0
2 years ago
A cafeteria used 63.50 kilograms of beans to make 5 batches of chili. How many kilograms of beans were used in each batch of chi
Vilka [71]
The word problem gives you the information you need to solve it.

5 batches of chili were made using 63.5 kg of beans total. You can assume the same amount of beans were used in each of the 5 batches, so ...

your equation would be:

63.5 ÷ 5 = # of beans in each batch.

63.5 ÷ 5 = 12.7

12.7 kg of beans were used in each of the 5 batches.

Check step:

12.7 × 5 = 63.5


6 0
2 years ago
In mathematics, the Nth harmonic number is defined to be 1 + 1/2 + 1/3 + 1/4 + ... + 1/N. So, the first harmonic number is 1, th
Andreyy89

Answer:

cl   +   1/(N+1)

Step-by-step explanation:

If we assume that the Nth harmonic number is cl. Then we are assuming that 1+1/2+1/3+1/4+...+1/N=cl

And we know that the (N+1)th harmonic number can be found by doing

1+1/2+1/3+1/4+...+1/N+1/(N+1)

=cl    +   1/(N+1)

The (N+1)th harmonic number is cl   +   1/(N+1) given that the Nth term is cl

Other way to see the answers:

Maybe you want to write it as a single fraction so you have

[cl(N+1)+1]/(N+1)=[cl*N+cl+1]/(N+1)

3 0
2 years ago
HELP MEEEEE!!! I HAVE AN F
mariarad [96]

Answer:

B is your answer!

Step-by-step explanation:

Hope I helped:)

6 0
2 years ago
1 kilogram is equivalent to about 2.2 pounds. An orangutan weighs 142 pounds. What is its mass in kilograms? Round your answer t
snow_lady [41]

The mass of orangutan is 64.5 kilograms

<em><u>Solution:</u></em>

Given that orangutan weighs 142 pounds

Also given that,

1 kilogram is equivalent to about 2.2 pounds

Now let us convert 142 pounds to kilograms

1 kilogram = 2.2 pounds

\text{1 pound } = \frac{1}{2.2} \text{ kilograms }

Therefore, 142 pounds is equivalent to,

142 \text{ pound } = \frac{1}{2.2} \times 142 \text{ kilogrmas }

\rightarrow \frac{1}{2.2} \times 142 = 64.545 \text{ kilograms }

On rounding to nearest tenth we get, 64.5 kilograms

Thus mass of orangutan is 64.5 kilograms

3 0
2 years ago
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