All categories

1 year ago

The graph of which function has a minimum located at (4, –3)?

Mathematics

2 answers:

lions [1.4K]1 year ago

7 0

Answer:

Step-by-step explanation:

In order to solve the question, we have to derivate each function.

1) f(x) = x2 +4x -11

Then,

f'(x)= 2x +4

Now, if f'(4)=0 we would have a critical point, which could be a minimum. Let's find out:

f'(4)= 2*4 +4 = 12 ≠ 0 then this function doesn't not have a minimum at (4, -3)

2) f(x) = –2x2 + 16x – 35

Then,

f'(x)= -4x +16

Now, if f'(4)=0 we would have a critical point, which could be a minimum. Let's find out:

f'(4)= -4*4 16 = 4 ≠ 0 then this function have a critical point at (4, -3)

then,

f''(4) =-4 <0 then we have a minimum at (4, -3)

3) f(x) = x2 – 4x + 5

Then,

f'(x)= 2x -4

Now, if f'(4)=0 we would have a critical point, which could be a minimum. Let's find out:

f'(4)= 2*4 -4 = 4 ≠ 0 then this function doesn't not have a minimum at (4, -3)

4) f(x) = 2x2 – 16x + 35

Then,

f'(x)= 4x -16

Now, if f'(4)=0 we would have a critical point, which could be a minimum. Let's find out:

f'(4)= 4*4 -16 = 4 ≠ 0 then this function doesn't not have a minimum at (4, -3)

Oksanka [162]1 year ago

5 0

It is the third option on Edge

You might be interested in

Day care centers expose children to a wider variety of germs than the children would be exposed to if they stayed at home more o

USPshnik [31]

Answer:

a) This is an Observational Study because in this kind of study investigators observe subjects and measure variables of interest without assigning treatments to the subjects. Here, the Gilham et al. (2005) studied two different groups where no treatment or intervention was done. These groups were independent of each other.

b) proportions of children with significant social activity in children with acute lymphoblastic leukemia = 1020/1272 = 0.80

proportions of children with significant social activity in children without acute lymphoblastic leukemia = 5343/6238 = 0.86

c) Odds ratio can be calculated using the following formula:

OR= \frac{a/b}{c/d}

where: a - Number in exposed group with positive outcome(here this means number of children with significant social activity associated with acute lymphoblastic leukemia)

b- Number of children without social activity having with acute lymphoblastic leukemia

c- Number of children with social activity having without acute lymphoblastic leukemia

d- Number of children without social activity having without acute lymphoblastic leukemia

OR= \frac{1020/252}{5343/895}

OR= 0.6780

d) The 95% confidence interval of this Odds Ratio is 0.5807 to 0.7917.

e) Since the odds ratio lies in this confidence interval indicate that the amount of social activity is associated with acute lymphoblastic leukemia. The children with more social activity have a higher occurrence of acute lymphoblastic leukemia.

8 0

1 year ago

A camera manufacturer spends $2,000 each day for overhead expenses plus $9 per camera for labor and materials. The cameras sell

mylen [45]

They must sell 250 cameras
and 50 more cameras would be a $400 profit

6 0

1 year ago

Read 2 more answers

The Weston Laundry washes all the linens for local hotels. In 7 days, they washed 285.38 pounds of towels and 353.47 pounds of s

Serhud [2]

In the problem it is already given that Weston Laundry washed 285.38 pounds of towel and 353.47 pounds of sheets from local hotels in 1 day. Firstly we have to find the total pounds of linens that Weston Laundry has washed in 7 days. Then only will it be possible to find the amount of linen washed in a day.
Then t
Total linen washed by Weston Laundry in 7 days = (285.38 + 353.47) pounds
= 638.85 pounds.
Then
The amount of linen washed by Weston Laundry in 1 day = 638.85/7
= 91.26 pounds
So Weston Laundry washed about 91.26 pounds of linen each day.

4 0

1 year ago

The area of a small pond is 78.5 yds. What is the diameter of the pond?

Zolol [24]

Answer:

Diameter of pound = 10 yd

Step-by-step explanation:

Given area of circular pond = 78.5 square yd

To find the diameter of the pond.

Solution:

The pond being circular in shape, the area of pond can be given as:

⇒ $\pi\ r^2$