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rewona [7]
2 years ago
14

mrs brown has 1/3 yd of blue denim and 1/2 yd of black demin. how many purses can be made using denim as the main fabric

Mathematics
1 answer:
Galina-37 [17]2 years ago
8 0
Sorry at the end of the day i gotta get points to ask questions...sorry hope you find your answer
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lucas and erick are factoring the polynomial 12x3 – 6x2 8x – 4. lucas groups the polynomial (12x3 8x) (–6x2 – 4) to factor. eric
Maurinko [17]

Answer:

Both the students were correct.

Step-by-step explanation:

Given : The polynomial is - 12 x^3 - 6 x^2 + 8 x - 4

To find : Who correctly grouped the terms to factor.

Lucas group the polynomial - ( 12 x^3 + 8 x ) + ( - 6 x^2 - 4 )

Now, we solve the Lucas polynomial

(12x^3+8x) + (-6x^2-4)= 4x(3x^2+2 )-2(3x^2+2)

(12x^3+8x) + (-6x^2-4)= (3x^2+2 )(4x-2)

(12x^3+8x) + (-6x^2-4)= 2(3x^2+2)(2x-1)

Erick group the polynomial - (12x^3-6x^2) + (8x- 4)

Now, we solve the Erick polynomial

(12x^3-6x^2) + (8x- 4)=6x^2(2x-1)+4(2x-1)

(12x^3-6x^2) + (8x- 4)=(6x^2+4)(2x-1)

(12x^3-6x^2) + (8x- 4)=2(3x^2+2)(2x-1)

The factors of Lucas and Erick are same.

Each grouping leads to the same result. 

Therefore, Both students are correct.

8 0
2 years ago
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The graph of the function f is shown. f(3) =
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A regional director responsible for business development in the state of Pennsylvania is concerned about the number of small bus
lisabon 2012 [21]
Since the probability of failure is an independent event, this follows a Poisson distribution, where the mean is 8.8 and the given x = 4:
P(k) = \frac{e^{-\lambda}(\lambda)^{k}}{k!} \\ P(4) = \frac{e^{-8.8}(8.8)^{4}}{4!} = 0.0377
3 0
2 years ago
Suppose that for a recent admissions class, an Ivy League college received 2,851 applications for early admission. Of this group
stepan [7]

Answer:

A) The probability is a measure of the likelihood than an event is going to occur. In this case we can calculate the probability of X as:

P(X) = X/N where X is the number of ways X occurs and N is the total number of events.

P(E) = E/N = 1033/2851 = 0.3623

P(R) = R/N = 854/2851 = 0.2995

P(D) = D/N = 964/2851 = 0.3381

B)

E and D are mutually exclusive because the students that were admitted early where not deffered to regular admission pool. There is no chance that there is a student that were admitted erarly and deffered at the same time, so the intersection between E and D (E∩D) is 0.

C) The number of students that were early accepted is 1033 and the total number of students accepted is 2375. The probability is going to be:

P = 1033/2375 = 0.4349

D)

In this case we can reformulate the question as: What is the probability of being accepted if you apply for early admission? This

Since 18% of the students deffered to regular admission pool 0.18 × 964 = 174 were admitted at the end.

The probability of being deffered and then accepted is going to be:

P(DA) = 174/2831 = 0.0610

The probability of ramdomly selecting a students that has been early accepted or deffered and then accepted is going to be:

P(E or DA) = 0.0610 + 0.3623 = 0.4233

This is the addition rule.

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2 years ago
Ellen thinks that if a line has no slope, then it never touches the y-axis. Which line proves that her statement is incorrect?
Jlenok [28]

Answer:  y+0

As y=0 represent x-axis whose slope is 0 and intersects y-axis at the origin.

Step-by-step explanation:

6 0
2 years ago
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