Given that Roger is building a storage shed with wood blocks that are in the shape of cubic prisms.
cube is basicallye a box which is made of squares. That is all the sides (lenght, width and height) are equal.
Now we have to determine, Can he build a shed that is twice as high as it is wide.
that means if width is 1 then height should be twice which is 2.
yes that is possible if we put one cubical prism over another cubical prism. then height of shed due to two prism will be twice than the width.
Hence correct choice should be "A. Yes. For every block of width, he could build two blocks high."
Answer:
$391
Step-by-step explanation:
Answer: The first equation should be multiplied by 9 and the second equation by −4, to eliminate the y-terms and solve for x in the fewest steps.
Step-by-step explanation:
Given : Equation (1) 5x − 4y = 28
Equation (2) 3x - 9y = 30
to eliminate the y-terms and solve for x in the fewest steps, we should multiply equation (1) by 9 and equation (2) by -4 such that
9(5x − 4y) =9 (28)⇒45x-36y=252
-4(3x - 9y) = -4(30)⇒ -12x+36y= -120
Now adding both equations, y-term eliminated and we get, 45x-12x=132
⇒33x=132⇒x=4.
Answer:
Jackie sold 12 cars.
Step-by-step explanation:
If we call the number of cars Oscar sold O, and the number of cars Jackie sold J, we can say the following:
O = J + 6
As Oscar sold 6 cars more than Jackie.
Together, they sold 30 cars.
O + J = 30
Since we know that:
O = J + 6
... we can put this into our previous equation.
O + J = 30
(J + 6) + J = 30
J + J + 6 = 30
2 * J + 6 = 30
Subtract 6 from both sides:
2 * J = 24
Divide both sides by 2:
J = 24 / 2
J = 12
Jackie sold 12 cars.
<span>Using the kinematic equations:
(final velocity)^2 = (initial velocity)^2 - 2 * acceleration * distance
Assuming the acceleration/deceleration on the car is constant from a constant force on the brakes. Converting from mph to m/s using 0.447 (so 34 mph is 15.2 m/s)
(0)^2 = (15.2)^2 - 2 * acceleration * 29
acceleration = 4.0 m/s^2
Had the car been going 105.4 mph (47.1 m/s)
(0)^2 = (47.1)^2 - 2 * 4 * distance
distance = 277 meters</span>
