Answer:
The side length of the original square was 6 inches
Step-by-step explanation:
we know that
The area of a square is

where
b is the length side of the square
Let
x ---> the length of the original square
The area of the original square is

The length of the smaller square is

The area of the smaller square is

The area of the smaller square is 1/4 the area of the original square
so

solve for x

Multiply by 4 both sides


Solve the quadratic equation by graphing
using a graphing tool
x=2, x=6
see the attached figure
The solution is x=6 in
Remember that the solution must be greater than 3 inches (because Stacey cuts 3 inches off of the length of the square and 3 inches off of the width)
therefore
The side length of the original square was 6 inches
Answer:

Step-by-step explanation:
<u>Right Triangles
</u>
In a right triangle, one of the internal angles is 90°. When this happens, there is always a longer side, called hypotenuse and two shorter sides, called legs. They relate to Pythagoras's theorem. The basic trigonometric relations also stand, including
where a is the opposite leg to
and c is its adjacent led .
In our problem, we have a statue being looked by a person in such a way that the top of the statue forms an angle of 8° with the horizontal and the base of the statue forms an angle of 14° down. We also know the distance from the person to the statue is 50 ft. The situation is shown in the image below.
The height of the statue is h=a+b, where
Thus
If we look at where it is now, we would have multiplied the x and y values by 1/2. since we are working backwards, lets multiply by 2 instead...giving us the vertex for the pre-image....
J is now (0, -2) multiply by 2
J was (0, -4)
Answer:
Each associate costs the client $700 per day, so a associates will cost the client 700a dollars per day. Each partner costs the client $1500 per day, so p partners will cost the client 1500p dollars per day. The total amount charged 700a+1500p :$14100:
700a+1500p=14100
700a+1500p=14100
Since there were a total of 11 lawyers assigned to the case (associates and partners), we know a+pa+p must equal 11.11.
a+p=11
a+p=11
\underline{\text{Write System of Equations:}}
Write System of Equations:
700a+1500p=
700a+1500p=14100
14100
a+p=11
11