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KIM [24]
2 years ago
14

Alejandro would like to start a new business. His friends have suggested he go into merchandising. But he's confused about what

exactly
merchandising is. Which sentence provides Alejandro with the most accurate description of merchandising?

A. Merchandising is selling your skills, expertise, knowledge, and experience for money.
Mathematics
2 answers:
Andreyy892 years ago
7 0

Answer:

Step-by-step explanation:

This is the complete question

(Alejandro would like to start a new business. his friends have suggested he go into merchandising. but he's confused about what exactly

merchandising is. which sentence provides alejandro with the most accurate description of merchandising?

a.

merchandising is selling your skills, expertise, knowledge, and experience for money

b.

merchandising is selling a product bought at a wholesale price at a higher retail price

c.

merchandising is selling a product that you have created directly to your target customer.

d. merchandising is selling marketing ideas and advertising campaigns to other companies.

e. merchandising is selling a customized service to cater to a customer's needs and wants).

The most accurate description of what merchandising is option B, because it entails the selling of a product, bought at a whole sale price at a higher retail price through different approach such as offering promos or discounts, bargaining and even giving the customer first hand information about the product they are about to buy. Merchandising involves convincing the customer to buy a product in your shop while making profit from it.

disa [49]2 years ago
4 0

Answer:

b

Step-by-step explanation:

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The Fortune 500 is comprised of Fortune magazine's annual list of the finite population of the top 500 companies in the U.S. ran
Serjik [45]

Answer:

The standard error of the proportion is 0.0367.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the standard error is s = \sqrt{\frac{p(1-p)}{n}}

In this question:

p = 0.16, n = 100

So

s = \sqrt{\frac{0.16*0.84}{100}} = 0.0367

The standard error of the proportion is 0.0367.

4 0
1 year ago
We're testing the hypothesis that the average boy walks at 18 months of age (H0: p = 18). We assume that the ages at which boys
marusya05 [52]

Answer:

II. This finding is significant for a two-tailed test at .01.

III. This finding is significant for a one-tailed test at .01.

d. II and III only

Step-by-step explanation:

1) Data given and notation    

\bar X=19.2 represent the battery life sample mean    

\sigma=2.5 represent the population standard deviation    

n=25 sample size    

\mu_o =18 represent the value that we want to test    

\alpha represent the significance level for the hypothesis test.    

t would represent the statistic (variable of interest)    

p_v represent the p value for the test (variable of interest)    

2) State the null and alternative hypotheses.    

We need to conduct a hypothesis in order to check if the mean battery life is equal to 18 or not for parta I and II:    

Null hypothesis:\mu = 18    

Alternative hypothesis:\mu \neq 18    

And for part III we have a one tailed test with the following hypothesis:

Null hypothesis:\mu \leq 18    

Alternative hypothesis:\mu > 18  

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:    

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)    

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".    

3) Calculate the statistic    

We can replace in formula (1) the info given like this:    

z=\frac{19.2-18}{\frac{2.5}{\sqrt{25}}}=2.4    

4) P-value    

First we need to calculate the degrees of freedom given by:  

df=n-1=25-1=24  

Since is a two tailed test for parts I and II, the p value would be:    

p_v =2*P(t_{(24)}>2.4)=0.0245

And for part III since we have a one right tailed test the p value is:

p_v =P(t_{(24)}>2.4)=0.0122

5) Conclusion    

I. This finding is significant for a two-tailed test at .05.

Since the p_v. We reject the null hypothesis so we don't have a significant result. FALSE

II. This finding is significant for a two-tailed test at .01.

Since the p_v >\alpha. We FAIL to reject the null hypothesis so we have a significant result. TRUE.

III. This finding is significant for a one-tailed test at .01.

Since the p_v >\alpha. We FAIL to reject the null hypothesis so we have a significant result. TRUE.

So then the correct options is:

d. II and III only

6 0
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NeTakaya

Answer:

1/100

Step-by-step explanation:

It's because he and his 9 friends so 10 people each by 10 tickets. Ten times ten is 100 so it is one out of one-hundred.

3 0
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