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goblinko [34]
1 year ago
8

Consider the function represented by the equation y-6x-9=0. Which answer shows the equation written in function notation with x

as the independent variable?A. f(x)=6x+9B. f(x)=1/6x+3/2C. f(y)=6y+9D. f(y)=1/6y+3/2
Mathematics
2 answers:
Paha777 [63]1 year ago
8 0

Answer:

x^{2} \sqrt{x} \neq \sqrt[n]{x} \pi \alpha \frac{x}{y} x_{123}

Step-by-step explanation:

Marta_Voda [28]1 year ago
5 0

Answer:

A. f(x) = 6x + 9

Step-by-step explanation:

The given equation is:

y - 6x - 9 = 0

We have to write this equation in function notation with x as the independent variable. This means that y will be replaced by f(x) and all other terms will be carried to the other side of the equation to get the desired function notation.

y - 6x - 9 = 0

y = 6x + 9

f(x) = 6x + 9

Therefore, option A gives the correct answer.

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Which statement follows from the given theorem? Theorem: The diagonal of a parallelogram divides it into two congruent triangles
777dan777 [17]

Answer with explanation:

Theorem : The diagonal of a parallelogram divides it into two congruent triangles.

Properties of parallelogram

1. Opposite sides are equal and parallel.

2. Diagonal bisect each other.

3. Opposite Angles are equal.

If you will look at the first three options

A:  Diagonals of a parallelogram bisect opposite angles.→→False(Alternate angles are equal)

B: Consecutive sides of a parallelogram are congruent.→→→False(Opposite sides are congruent)

C: Consecutive angles of a parallelogram are congruent.→→→False(Opposite angles are congruent)

D: Consecutive angles of a parallelogram are supplementary.→→→→True

For,any parallelogram, having vertices , A, B and C and D

Opposite sides are parallel, so

1.∠A + ∠B=180°

2.∠C + ∠B=180°

3.∠C+ ∠D=180°

4. ∠A + ∠D=180°

Option D

6 0
2 years ago
A marina is in the shape of a coordinate grid. Boat A is docked at (2.4, −3) and Boat B is docked at (−3.4, −3). The boats are _
prisoha [69]

Answer:

5.8

Step-by-step explanation:

3 0
2 years ago
The sound intensity of rustling leaves is 100 times the reference intensity. Use your graph to determine the sound intensity of
wariber [46]

The sound intensity of rustling leaves,  y = 20 decibels

<u>Step-by-step explanation:</u>

y = 10logx

The sound intensity of rustling leaves is 100 times the reference intensity.

x = ratio of intensity of sound to reference to intensity

x = 100:1 or x = 100

y = 10 log(100) = 10 * 2 = 20 decibels

y = 20 decibels

4 0
1 year ago
Read 2 more answers
1. Write 3,876,943,000 using scientific notation.
Sunny_sXe [5.5K]

Answer:

3.876943x10^9

7.317x10^-4

Step-by-step explanation:

3,876,943,000

Put the decimal at the end

3,876,943,000.

Move it so only 1 number is before the decimal

3.876943000

We moved it 9 places, so that is the exponent

We moved it to the left, so the exponent is positive

The three zeros at the end can be dropped because they are the last numbers to the right of the decimal

3.876943x10^9

0.0007317

Move it so only 1 number is before the decimal

00007.317

We moved it 4 places, so that is the exponent

We moved it to the right, so the exponent is negative

The four zeros at the left can be dropped because they are the last numbers to the left of the whole number

7.317x10^-4

8 0
2 years ago
1) Mrs. Merson is selling her car. Her research shows that the car has a current value of $5,500,
SVEN [57.7K]

The right answer is Option B:  \frac{5500}{p}=\frac{55}{100}

Step-by-step explanation:

Given,

Current value of car = $5500

This is 55% of the original value.

Let,

p be the original price of car.

Therefore,

55% of p = 5500

\frac{55}{100}p=5500

Dividing both sides by p

\frac{55}{100}*\frac{p}{p}=\frac{5500}{p}\\\frac{55}{100}=\frac{5500}{p}

The equation \frac{5500}{p}=\frac{55}{100} can be used to find the price Mrs. Merson paid for the car.

The right answer is Option B:  \frac{5500}{p}=\frac{55}{100}

Keywords: percentage, division

Learn more about percentages at:

  • brainly.com/question/13062539
  • brainly.com/question/13076219

#LearnwithBrainly

0 0
2 years ago
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