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goblinko [34]
2 years ago
8

Consider the function represented by the equation y-6x-9=0. Which answer shows the equation written in function notation with x

as the independent variable?A. f(x)=6x+9B. f(x)=1/6x+3/2C. f(y)=6y+9D. f(y)=1/6y+3/2
Mathematics
2 answers:
Paha777 [63]2 years ago
8 0

Answer:

x^{2} \sqrt{x} \neq \sqrt[n]{x} \pi \alpha \frac{x}{y} x_{123}

Step-by-step explanation:

Marta_Voda [28]2 years ago
5 0

Answer:

A. f(x) = 6x + 9

Step-by-step explanation:

The given equation is:

y - 6x - 9 = 0

We have to write this equation in function notation with x as the independent variable. This means that y will be replaced by f(x) and all other terms will be carried to the other side of the equation to get the desired function notation.

y - 6x - 9 = 0

y = 6x + 9

f(x) = 6x + 9

Therefore, option A gives the correct answer.

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Vicky's checking account charges a $12.25 monthly service fee and a $0.26
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Particle travels along a circular path that has a radius of 3 feet. The angular velocity of the particle is 18 radians per minut
Gala2k [10]
We know that

[length of a circumference ]=2*pi*r
for r=3 ft

[length of a circumference ]=2*pi*3-----------> 18.84 ft

<span>The angular velocity of the particle is 18 radians per minute.

if 2pi radians  (full circle)------------------> 18.84 ft
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the answer is
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6 0
1 year ago
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The number of defective components produced by a certain process in one day has a Poisson distribution with a mean of 20. Each d
Kruka [31]

Answer:

The probability that exactly 15 defective components are produced in a particular day is 0.0516

Step-by-step explanation:

Probability function : P(X=x)=e^{-\lambda} \frac{\lambda^x}{x!}

We are given that The number of defective components produced by a certain process in one day has a Poisson distribution with a mean of 20.

So,\lambda = 20

we are supposed to find the probability that exactly 15 defective components are produced in a particular day

So,x = 15

Substitute the values in the formula :

P(X=15)=e^{-20} \frac{20^{15}}{15!}

P(X=15)=e^{-20} \frac{20^{15}}{15!}

P(X=15)=0.0516

Hence the probability that exactly 15 defective components are produced in a particular day is 0.0516

8 0
2 years ago
Use the scale factor 1:8 to find the missing dimension. Item Model Actual Baby Giraffe Height: cm Height: 1.84 m
Illusion [34]

Answer:

h^{*} = 0.23\,m

Step-by-step explanation:

The scale factor described denotes a reduction operation. The missing dimension is given by simple rule of three:

h^{*} = \frac{1}{8}\cdot (1.84\,m)

h^{*} = 0.23\,m

3 0
2 years ago
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