Answer:
post zygotic barrier by hybrid inviability
Explanation:
Post zygotic barriers are involves creation of offsprings that will not survive either
- Hybrid inviability- will not survive past the embryonic stages
- Hybrid sterility- Individuals will survive but they will fail to produce offsprings
In the case where mice belonging to the same genus mate but their offspring fail to develop normally is a good example of Post-zygotic barrier by hybrid inviability
It was ancient fossils containing ----Ancient bacteria---
Answer:
C. 1/4
Explanation:
Let's assume that the allele for the spotted coat is "S" and the one for the even coat is "s". The allele "L" gives short horns while the recessive allele "l" imparts long horns. The genotype of the cattle heterozygous for both traits would be SsLl. A cross between two heterozygous cattle would produce progeny in following phenotype ratio=
9 spotted coat and short horns: 3 even coat and short horns: 3 spotted coat and long horns: 1 even coat and long horns.
Therefore, the proportion of the progeny with long horns = 4/16= 1/4
Answer:
This protein doesn't have a secondary structure (i.e., alpha helices or beta sheets), thereby it interacts with the specific molecule trough its loops
Explanation:
Protein loops may interact with diverse molecules including nucleic acids (RNA and DNA), proteins, signal molecules, etc. These protein sequences (loops) interact with both polar and non-polar head groups
