Consider one pyramid
Side length of base = 1.5cm and its height is 1 cm
Slant height of one of the lateral faces = sqrt(1^2 + 0.75^2) = 1.25 cm
Area of one of the triangular faces = 0.5 * 1.5* 1.25 = 0.9375 cm^2
There are 8 of these so the required surface area = 8 * 0.9375
= 7.5 cm^2 Answer
The volume (when x = 10) would be 1,000 cubic units (10^3).
(i) speed = distance / time
so time = distance / speed
here we have
time t = 1080/x hours
(ii) return flight time = 1080 / (x + 30) hours
(a) 1080/x - 1080/(x + 30) = 1/2
Multiplying through by the LCD 2x(x + 30) we get:-
1080*2(x + 30) - 2x*1080 = x(x+30)
2160x + 64800 - 2160x = x^2 + 30x
x^2 + 30x - 64800 = 0
(b) factoring; -64800 = 270 * -240 ans 270-240 = 30 so we have
(x + 270)(x - 240) = 0 so x = 240 ( we ignore the negative -270)
So the speed for outward journey is 240 km/hr
(c) time ffor outward flight = 1080 / 240 = 4 1/2 hours
(d) average speed for whole flight = distance / time
Time for outward journey = 4.5 hours and time for return journey = d / v
= 1080 / (240+30) = 4 hours
Therefore the average speed for whole journey = 2160 / 8.5 = 254.1 km/hr
Answer:
in units: 18,900
in dollars: $ 41,013
Step-by-step explanation:
The break even point is the sales dollar amount or sales in unit at whichthe operating income of the firm equals to zero:
Where:

<em><u>Contribution margin:</u></em>
2.17 - 1.27 = 1 dollar per unit
Break even:
$18,900 fixed cost / $1 per unit = 18,900 units
Then, in sales:
18,900 x $2.17 each = 41.013
break even point:
<span>Given data shows that 1/3 time less time for fans to exit a game as it does for them to enter and find their seats.
Ingress for the stadium = 3,000 fans per hour
Ingress rate = (1 - 1/3) x Egress rate = 2/3 Egress rate
Egress rate = 3/2 ingress rate = 3/2 x 6,000 = 9,000 fans per hour</span>