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2 years ago

4

40% of a nurse's time is spent dispensing medicine to patients. If 16 hours per week is spent dispensing medicine, how many hour

s does the nurse work?

2 answers:

Monica [59]2 years ago

5 0

Answer:

40 hours per week

Step-by-step explanation:

Hello, I can help you with this.

you can easily solve this by using a simple rule of three

Step 1

define

Let

100% of a nurse's time = number of hours she works per week

if

40% of a nurse's time⇔16 hours

100% of a nurse's time⇔x? hours

the relation is

$\frac{40}{16}=\frac{100}{x}\\solve\ for\ x\\\frac{x*40}{16}=100\\x*40=100*16\\x=\frac{100*16}{40}\\ x=\frac{1600}{40}\\ x=40$

the 100% of a nurse's time is 40 hours, it means that a nurse works 40 hours per week.

have a great day

Gekata [30.6K]2 years ago

4 0

X= total hrs worked in a week

40x/100 = 16

40x=1600

x = 1600/40

x= 40 hrs

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A teacher reviews 4-1/2 papers per hour, how many papers will that teacher review in 6-1/3 hours

MrRa [10]

Answer:

$28\frac{1}{2}\ papers$

Step-by-step explanation:

step 1

Convert mixed numbers to an improper fractions

$4\frac{1}{2}=\frac{4*2+1}{2}=\frac{9}{2}$

$6\frac{1}{3}=\frac{6*3+1}{3}=\frac{19}{3}$

step 2

we know that

A teacher reviews 9/2 papers per hour

using proportion

Find how many papers will the teacher review in 19/3 hours

Let

x-----> the number of papers

$(9/2)/1=x/(19/3)$

$x=(19/3)(9/2)$

$x=28.5\ papers$

Convert to mixed numbers

$28.5=28\frac{1}{2}\ papers$

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2 years ago

About how many more inches of rain did Asheville get than Wichita? About how many more days did it rain in Asheville than Wichit

zaharov [31]

Answer:

Par 1) 19.10 inches

Part 2) 39 days

Step-by-step explanation:

we know that

Asheville

47.71 in

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Wichita

28.61 in

85 days

Part 1) About how many more inches of rain did Asheville get than Wichita?

In this part subtract the number of inches of rain in Wichita from the number of inches of rain in Asheville

so

$47.71-28.61=19.10\ in$

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$124-85=39\ days$

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2 years ago

Haley and Nicole stopped at the school bookstore for extra supplies. Haley bought 8 pencils and 3 folders and spent $10.39. Nico

Harlamova29_29 [7]

I believe it is 12 cents

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2 years ago

An aircraft travels with the wind for 120 miles in 0.75 of an hour. The return trip is flown against the wind and takes exactly

7nadin3 [17]

<span>n aircraft travels with the wind for 120 miles in 0.75 of an hour. The return trip is flown against the wind and takes exactly 1 hour.
Which system of linear equations represents x, the speed of the plane in miles per hour, and y, the speed of the wind in miles per hour?
---
With wind DATA:
distance = 120 miles ; time = (3/4)hr ; rate = 120/(3/4) = 160 mph
----
Against wind DATA:
distance = 120 miles ; time = 1 hr ; rate = 120 mph
-----

Equation::
Let p be speed of the plane in still air
Let w be speed of the wind
==================================
With wind:: p + w = 160 mph
Against wind:: p - w = 120 mph
================================
</span>

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2 years ago

Read 2 more answers

Eudora ran from her home to her secret laboratory at an average speed of 12\text{ km/h}12 km/h12, start text, space, k, m, slash

OleMash [197]

Answer:

Eudora spent 0.5 hours from home to library and 1.5 hours from library to school

Step-by-step explanation:

Given

Home to Library:

$S_1 = 12km/h$ -- Average Speed

Library to School

$S_2 = 76km/h$ -- Average Speed

Total

$Distance = 120km$

$Time = 2\ hr$

Required

Determine the time taken from home to library and from library to school

Let the time spent from home to library be x. So, from library to school will be: 2 - x

So, we have:

Home to Library:

$S_1 = 12km/h$ -- Average Speed

$T_1 =x$ -- Time

Library to School

$S_2 = 76km/h$ -- Average Speed

$T_2 =2 - x$ -- Time

Distance is calculated as:

$Distance = Speed * Time$

Home to Library:

$D_1 = S_1 * T_1$

$D_1 = 12 * x$

$D_1 = 12x$

Library to School:

$D_2 = S_2 * T_2$

$D_2 = 76 * (2- x)$

$D_2 = 152- 76x$

The total distance is 120km. So, we have:

$120km = D_1 + D_2$

$120 = 12x + 152 - 76x$

Collect Like Terms

$120 - 152 = 12x - 76x$

$-32 = -64x$

$-64x=-32$

Solve for x

$x = \frac{-32}{-64}$

$x = 0.5$

Recall that:

$T_1 =x$

$T_2 = 2 - x$

So, we have:

$T_1 = 0.5$

$T_2 = 2 -0.5 = 1.5$

4 0

1 year ago