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olga nikolaevna [1]
2 years ago
6

Heidi solved the equation 3(x + 4) + 2 = 2 + 5(x – 4). Her steps are below: 3x + 12 + 2 = 2 + 5x – 20 3x + 14 = 5x – 18 14 = 2x

– 18 32 = 2x 16 = x Use the drops-downs to justify how Heidi arrived at each step
Mathematics
2 answers:
Delvig [45]2 years ago
7 0
1. Distributive Property
2. Combine Like Terms
3. Subtraction Property
4. Addition Property
5. Division Property
konstantin123 [22]2 years ago
5 0
First, she distributed 3*x=3x , 3*4=12, 5*x= 5x, 5* -4= -20
Which gave her 3x+12+2=2+5x-20
Then, she combined like terms 12+2=14 and 2+ -20 = -18
Which gave her 3x+14=5x-18
Then, she subtracted 3x from both sided 
Which gave her 14=2x-18
Then, she added 18 to both sides
Which gave her 32=2x
And finally sh edivided 32 by 2 and got 16=x
hope this helps if you have any questions please pm me :)
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RSB [31]

Answer:

So, the number that Lin multiplied by 7/8 MUST be less than 1. This is evident, as any positive number multiplied by a number less than 1 will decrease, doesn't matter if its a negative or positive number.

Step-by-step explanation:

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2 years ago
Every day, Jorge buys a lottery ticket. Each ticket has a probability of of winning a prize. After six days, what is the probabi
Romashka [77]

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

Every day, Jorge buys a lottery ticket. Each ticket has a 0.16 probability of winning a prize. After six days, what is the probability that Jorge has won at least one prize? Round your answer to four decimal places.

Answer:

The probability that Jorge has won at least one prize after six days is

P(at least 1 win) = 0.6487

Step-by-step explanation:

Every day, Jorge buys a lottery ticket which has a 0.16 chance of winning a prize.

We want to find out the probability that Jorge has won at least one prize after six days.

P(at least 1 win) = 1 - P(not winning for 6 days)

We know that the probability of winning is 0.16 then the probability of not winning is

P(not winning) = 1 - 0.16 = 0.84

For 6 days,

P(not winning for 6 days) = 0.84×0.84×0.84×0.84×0.84×0.84

P(not winning for 6 days) = 0.84⁶

P(not winning for 6 days) = 0.3513

Finally,

P(at least 1 win) = 1 - P(not winning for 6 days)

P(at least 1 win) = 1 - 0.3513

P(at least 1 win) = 0.6487

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