Question

The function f(x)=5(x−1) is shown on the coordinate plane. Select from the drop-down menus to correctly describe the end behavior of ​ f(x) ​. As x decreases without bound, the graph of f(x) . As x increases without bound, the graph of f(x) . An exponential curve graphed on a coordinate plane with horizontal x-axis ranging from negative 4 to 4 in increments of 1. The vertical y-axis ranges from negative 5 to 5 in increments of 1. The curve begins from the second quadrant. The curve increases through begin ordered pair 0 comma 0.2 end ordered pair. The curve passes through begin ordered pair 1 comma 1 end ordered pair and moves away from the positive y-axis.

Answer 1

Answer: As x decreases without bound the graph f(x) decreases, as x increases without bound the graph of f(x) increases.

Step-by-step explanation:

Since, the given function is , $f(x) =5(x-1)$

If $x\rightarrow -\infty$ then $f(x)\rightarrow -\infty$

that is, we can say, as x decreases without bound the graph f(x) decreases.

While, If $x\rightarrow +\infty$ then $f(x)\rightarrow +\infty$

That is, we can say, as x increases without bound the graph f(x) increases.

thus, we can say first option represents the correct end behavior of f(x).

Answer 2

Since the graph is not given, I am going off of the functionf(x) = 5(x-1)

This is a linear graph, a straight line, since x and f(x) is one degree. The slope is positive which means it is increasing from the left to the right. 

It looks like the answers have been cut off, but as x increases with out bound, the value of f(x) will increase. As x decreases without bound the value of f(x) will also decrease.