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Scilla [17]
2 years ago
4

Please help me with problem

Mathematics
1 answer:
Alexus [3.1K]2 years ago
8 0
Okay. The square root of 2 is between the square root of 1 and 4, which is greater than 1, but less than 2. In decimal form, that is about 1.41, which is greater than 1.4. 3/4 (0.75) is less than 0.7575757575, because 3/4 terminated, while the other decimal repeats. With that being said, here are the numbers ordered from least to greatest.

3/4, .75 decimal repeating, 1.4, square root of 2
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Which of the following best defines 3 to the power of 2 over 3?
Hatshy [7]
If the question is 3^(2/3), The answer is the cube root of 9.
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What is the following sum? 2 (RootIndex 3 StartRoot 16 x cubed y EndRoot) + 4 (RootIndex 3 StartRoot 54 x Superscript 6 Baseline
MissTica

Answer:

a on edge

Step-by-step explanation:

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Find a single expression that represents the area of the outer ring of the circle if the area of the whole circle is represented
sp2606 [1]

Answer:  The answer is A_o=2\pi\sqrt{\dfrac{7}{22}(25x^2-12x-9)}.


Step-by-step explanation: Given that the area of the whole circle is represented by the expression

A_c=25x^2-12x-9.

We are to find the area of the outer ring of the circle, i.e., to find the circumference of the circle.

Now, if 'r' represents the radius of the circle, then we have

A_c=\pi r^2\\\\\Rightarrow \dfrac{22}{7}r^2=25x^2-12x-9\\\\ \Rightarrow r^2=\dfrac{7}{22}(25x^2-12x-9)\\\\\Rightarrow r=\sqrt{\dfrac{7}{22}(25x^2-12x-9)}.

Thus, the area of the outer ring is

A_o=2\pi r=2\pi\sqrt{\dfrac{7}{22}(25x^2-12x-9)}.


5 0
2 years ago
my class collected 389 milk jugs. We used 40 jugs. We gave 30 milk to the first graders. how many milk jugs did we have?
BartSMP [9]
We will just do the following steps:-

389 - 40 = 349
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So, in the end your class had 319 milk jugs left.

Hope I helped ya!! 
8 0
2 years ago
Identify the equation of the circle that has its center at (10, 24) and passes through the origin.
marishachu [46]

Answer:

A )  The Equation of the circle (x−10)2+(y−24)2=676

Step-by-step explanation:

step1:-

The equation of the circle whose center is (a,b) and radius r is

(x-a)^{2} +(y-b)^{2} =r^{2}

(x-10)^{2}+(y-24)^{2}  =676

in this circle equation centre is (g,f) = (10,24)

and formula of radius of a circle is

r = \sqrt{g^{2}+f^{2} -c }

Step2:-

The Equation of the circle (x−10)^2+(y−24)^2=676

5 0
2 years ago
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