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lana66690 [7]
2 years ago
9

Describe the organization of skeletal muscle tissue from cell to whole muscle to groups of muscles

Biology
1 answer:
Lelu [443]2 years ago
5 0
<span>characteristics of skeletal muscle:</span><span>
contains nerve endings; is a voluntary muscle; striped/striated, multi-nucleated (has many nuclei); attached to the bones of the skeleton</span>
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ompared to eukaryotes, prokaryotes are ________. Compared to eukaryotes, prokaryotes are ________. simpler morphologically and m
Savatey [412]

Answer:

In compare to eukaryotes,prokaryotes are morphologically simpler,more evolutionary primitive,less sensitive to physical environment.

Explanation:

Prokaryotes are unicellular organism which don't possess cell organelle like nucleus,mitochondria,Endoplasmic reticulum,golgi body, etc.

They are the first living organism in the primitive earth and the genetic components are located in the cytoplasm which is enclosed by cell membrane.

prokaryotes contain 3 domains that are Archaea, bacteria and eukarya.

The cytoplasm is enclosed by cell membrane.

Molecular studies have reveal that eukaryotes are evolved from prokaryotes.

Some prokaryotes bear long projection which helps them for locomotion,called as flagellum.This is present in gram positive and gram negative bacteria.

7 0
2 years ago
Gyri and sulci are the ________ and ________, respectively, which characterize the surface of the human brain.
iren2701 [21]

<span>Gyri and sulci are the folds and grooves, respectively, which characterize the surface of the human brain.</span> Gyri are part of the brain that shows a larger surface of the brain. When the gyri change in structure or form it shows that a body is encountering sickness and disorders. Sulci is one of the part of the cerebral cortex that surrounds the gyri.  

3 0
2 years ago
Two autosomal genes, J and K, are 60 map units apart. You perform the following testcross: J K / j k x j k / j k. At what freque
Dmitry [639]

Answer:

  • J K / j k = 20%
  • j k / j k = 20%
  • J k / j k = 30%
  • j K / j k = 30%                

Explanation:

To calculate the recombination frequency, we have to know that 1% of recombinations = 1 map unit = 1cm. And that the maximum recombination frequency is always 50%.

The map unit is the distance between the pair of genes for which every 100 meiotic products, one of them results in a recombinant one.

So, en the exposed example:

  • J and K are autosomal genes
  • J and K are separated by 60 M.U.
  • 60 M.U. means that there is 60% of recombination.

Cross)             J K / j k                    x                  j k / j k

Gametes) JK  Parental                                     jk, jk, jk, jk

                jk   Parental                                  

                Jk   Recombinant                          

                 jK   Recombinant

One map unit equals 1% of recombination frequency. This means that every 100 meiotic products, one of them is a recombinant one.

1 M.U. -------------- 1% recombination

60 M.U. ------------ 60% recombination

                              30% Jk  +  30% jK

100 M.U. - 60 M.U. = 40 M.U.

40M.U.--------------40 % Parental (Not recombinant)

                            20% JK   +   20% jk

Punnet Square)           JK       jk      Jk      jK

                          jk     JK/jk   jk/jk   Jk/jk   jK/jk

J K / j k = 20%

j k / j k = 20%

J k / j k = 30%

j K / j k = 30%                                

3 0
2 years ago
What situation best represents how DNA sequencing, PCR, and gene probes might be used together? Multiple Choice Scientists might
Ivahew [28]

Answer:

Scientists might replicate a strand of DNA using PCR before sequencing it. Once the sequence is known, they can produce a corresponding gene probe

Explanation:

PCR refers to the polymerase chain reaction that amplifies the small sample of DNA into multiple copies in three steps. These steps are denaturation of sample DNA to produce single-stranded template strand, binding of primer to the template and elongation. The multiple copies of the sample DNA are then used to decipher its sequence using various sequencing methods.

Once the sequence of the sample DNA is known, the short, single-stranded DNA molecules that are complementary to the specific sequence of DNA are formed. These single-stranded DNA molecules are called DNA probe and are used to detect the specific nucleotide sequence in some other sample DNA.

8 0
2 years ago
Black widow spiders are considered the most venomous spiders in North America. They are roughly 1.5 inches long. Black widows ha
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The black widow spider is an invertebrate. Its skeleton system hangs outside its body. The only difference between a vertebrate and invertebrate is the presence of backbone or a similar kind of structure with in the body. In case of black widow spider, the internal structural element is missing.  Its skeleton system can be classified as exoskeleton.  

 

7 0
2 years ago
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