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Gwar [14]
2 years ago
4

Felicia wanted to find the number of boys in the school band if 30% of the 50 students are boys. Is her answer correct? Explain

why or why not. part whole = 30 × 2 100 × 2 = 60 200
Mathematics
2 answers:
N76 [4]2 years ago
4 0
There are 15 boys in the school band
Archy [21]2 years ago
4 0

Answer:

No, Felicia’s answer is not correct. She should have divided by 2, not multiplied. 30 divided by 2 is 15. So 15 of the 50 students in the band are boys.

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Two standardized​ tests, a and​ b, use very different scales of scores. the formula upper a equals 40 times upper b plus 50a=40×
Romashka [77]

Answer:

(a) The mean score of test A is 1210.

(b) The mean score of test A is 1210.

(c) The standard deviation of  test A is 80.

(d) The value of Q₃ for test A is 1170.

(e) The value of median for test A is 1090.

(f) The value of IQR for test A is 290.

Step-by-step explanation:

The relation between two standardized tests <em>A</em> and <em>B</em> is:

50A=40B+50

The equation above approximates the relationship between scores on the two tests.

The summary statistics for test B are as follows:

Lowest Score = 21

Mean score = 29

Standard deviation = 2

Q₃ = 28

Median = 26

IQR = 6

(a)

Compute the lowest score on test A as follows:

A=40B+50\\=(40\times21)+50\\=890

Thus, the lowest score on test A is 890.

(b)

Compute the mean score of test A as follows:

<h2>A=40B+50\\=(40\times29)+50\\=1210</h2>

Thus, the mean score of test A is 1210.

(c)

Compute the mean score standard deviation of test A as follows:

<h2>A=40B+50\\=(40\times2)\\=80</h2>

Thus, the standard deviation of  test A is 80.

(d)

Compute the value of Q₃ for test A as follows:

A=40B+50\\=(40\times28)+50\\=1170

Thus, the value of Q₃ for test A is 1170.

(e)

Compute the value of median for test A as follows:

A=40B+50\\=(40\times26)+50\\=1090

Thus, the value of median for test A is 1090.

(f)

Compute the value of IQR for test A as follows:

A=40B+50\\=(40\times6)+50\\=290

Thus, the value of IQR for test A is 290.

6 0
2 years ago
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Take me the brayniest.i hope it was helpful

7 0
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At the county fair, the operator of a game guesses a contestant’s weight. For each pound the operator’s guess differs from the c
BartSMP [9]

Answer:   | x - \frac{15}{3} | = 120  or \frac{1}{3}| 3 x - 15|= 120 or  | 3x - 15| = 360 or  | x - 5 | = 120

Step-by-step explanation:

Since, According to the question,

For each pound the operator’s guess differs from the contestant’s weight, the contestant will receive $3.

And, If a contestant weighing x pounds received $15

Then the guessed weight of contestant = | x - \frac{15}{3} |

But,  Again according to the question,

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⇒  | 3x - 15|= 3\times 120 (by multiplying 3 on both sides)

⇒  | 3x - 15|= 360

⇒  3| x - 5|= 360

⇒  | x - 5|= 120  ( On dividing both sides by 3 )

4 0
2 years ago
Read 2 more answers
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