The concentration of salt in water affects the rate of osmosis because it will determine how much water should be transported or excreted or to be taken in. The cellular process is keen to the salt concentration of its system thus making sure to maintain balance between the salt concentration the right amount of water must also be in its area of release for any expected occurences.
Osmosis then is the movement of water particles from which has water and from which has not and to provide it with the sufficient H2O.
Answer:
Q62.10
Explanation:
Medical coding is a translation. Coders for ease of work to medical doctors, takes medical reports from doctors,which entails doctors diagnosis, patients details and prescription, and the procedures the doctor are to give to the patient, and thereafter change or turn them into a set of codes. it is important as it helps medical doctors for ease of services to the patients. Medical coding is also in medical billing process and requires knowledge of technical know-how for its success.
Medical coding has the details of the full descriptions of diseases, injuries, and health care procedures from Doctors or physicians, health care providers and change them into numeric or alphanumeric codes to simplify and describe the diagnosis and the procedures to be performed on the patients.
Answer:
A serial dilution and the following plating experiment is done in order to determine the actual amount of bacteria/microbes in a specific volume of soil sample. As a standard test, a set volume of the lower dilution is obtained and positioned on a median plate and permitted to increase for the needed amount of time. The amount of colonies is evaluated and thus the overall Colony Forming Units (CFU) is determined by unit volume of the sample plated and therefore the volume of soil sample employed.
Therefore,
The calculation is done using:
CFU/ml = Number of colonies appeared × dilution factor / volume plated
Given,
Number of colonies appeared = 97
dilution factor = 10^(-6)
volume plated = 1/10 = 0.1
This will help us calculate it as:
CFU/ml = 97 * 10^(-6) / 0.1
= 97 * 10^(-7) CFU/ml
This CFU/ml helps determine the amount of bacterial colonies per unit volume of sample plated.
Given,
The original sample as 1g or 1000 mg of soil in its total volume.
Therefore,
The number of bacteria can be calculated using:
Amount of bacteria in original sample
= 97 * 10^(-7) CFU/ml × 1/ 1000 mg
= 9.7 * 10^(-3) CFU/mg
Answer:
13L:11D
Explanation:
Based on the photoperiod there are two types of plants -
a) Short day plant
b) Long day plant
Here the term short and long day do not mean that the provided length of day are the critical length of day required for reproduction. But opposite to that it means that the length of the day required for reproduction must be
a) Shorter than the defined length of day for short day plant
b) And longer than the defined length of day for long day plant
Chrysanthemums is a short day plant and thus option 1 with 13L:11D will produce fully developed flower buds
Option A is correct 13L:11D
Answer:
Option E, c is recessive to both c’ and c ch
Explanation:
As it is given in the question that when phenotypically c female rabbits are crossed with father with phenotype cch , the offspring produced have only cch phenotype which means that allele cch is dominant over allele “c”
Now in the F1 cross, when a female rabbit of phenotype c’ is crossed with cch male rabbit, then also c’ is expressed over “c” allele.
Hence, c is recessive to both c’ and cch allele
